Python 如何从JSON字符串中提取特定字段

Python 如何从JSON字符串中提取特定字段,python,json,python-2.7,Python,Json,Python 2.7,我有以下JSON字符串,我想获得doc\u count: import json text = '''{ "took": 1, "timed_out": false, "_shards": { "total": 5, "successful": 5, "failed": 0 }, "hits": { "total": 11, "max_score": 0, "hits": [] }, "aggregations": {

我有以下JSON字符串,我想获得
doc\u count

import json

text = '''{
  "took": 1,
  "timed_out": false,
  "_shards": {
    "total": 5,
    "successful": 5,
    "failed": 0
  },
  "hits": {
    "total": 11,
    "max_score": 0,
    "hits": []
  },
  "aggregations": {
    "range": {
      "buckets": [
        {
          "key": "2017-02-17T15:00:00.000Z-2017-02-17T16:00:00.000Z",
          "from": 1487343600000,
          "from_as_string": "2017-02-17T15:00:00.000Z",
          "to": 1487347200000,
          "to_as_string": "2017-02-17T16:00:00.000Z",
          "doc_count": 2
        }
      ]
    }
  }
}'''

obj = json.loads(text)

obj

我尝试了
obj['aggregations']['range']['bucket']['doc\u count']
,但它不起作用。如何搜索此JSON文件的层次结构?

您缺少一个事实,即
“bucket”
键包含一个列表。你需要:

obj['aggregations']['range']['buckets'][0]['doc_count']
obj['aggregations']['range']['buckets'][0]['doc_count']

请注意选择bucket键后的
[0]

您缺少一个事实,即
“bucket”
键包含一个列表。你需要:

obj['aggregations']['range']['buckets'][0]['doc_count']
obj['aggregations']['range']['buckets'][0]['doc_count']

请注意选择bucket键后的
[0]

因为
'bucket'
键包含元素数组。你需要


因为
“bucket”
键包含元素数组。你需要