Python TypeError:参数类型为';int';难道不可忍受吗?
我试图在Python2.7中编写一个hangman代码,我得到了类型错误 打印字符 对不起,我忘了添加其余的代码。这是完整的代码。这个词来自一个字典文件Python TypeError:参数类型为';int';难道不可忍受吗?,python,iterator,Python,Iterator,我试图在Python2.7中编写一个hangman代码,我得到了类型错误 打印字符 对不起,我忘了添加其余的代码。这是完整的代码。这个词来自一个字典文件 import random import string WORDLIST_FILENAME = "words.txt" def load_words(): print "Loading word list from file..." # inFile: file inFile = open(WORDLIST_FIL
import random
import string
WORDLIST_FILENAME = "words.txt"
def load_words():
print "Loading word list from file..."
# inFile: file
inFile = open(WORDLIST_FILENAME, 'r', 0)
# line: string
line = inFile.readline()
# wordlist: list of strings
wordlist = string.split(line)
print " ", len(wordlist), "words loaded."
return wordlist
def choose_word(wordlist):
return random.choice(wordlist)
wordlist = load_words()
print "Welcome to Hangman where your wits will be tested!"
name = raw_input("Input your name: ")
print ("Alright, " + name + ", allow me to put you in your place.")
word = random.choice(wordlist)
print ("My word has ")
print len(word)
print ("letters in it.")
guesses = 10
failed = 0
for char in word:
if char in guesses:
print char,
else:
print "_",
failed += 1
if failed == 0:
print "You've Won. Good job!"
break
#
guess = raw_input("Alright," + name + ", hit me with your best guess.")
guesses += guess
if guess not in word:
guesses -= 1
print ("Wrong! I'm doubting your intelligence here," + name)
print ("Now, there's only " + guesses + " guesses left until the game ends.")
if guesses == 0:
print ("I win! I win! I hanged " + name + "!!!")
您可以尝试:
if char in guesses:
但是,guesses
只是剩余猜测次数的计数,是一个整数,因此不能对其进行迭代。也许您还应该存储以前的猜测并使用:
guess_list = []
...
if char in guess_list:
...
guess_list.append(guess)
出于同样的原因,如果你走得那么远
guesses += guess
将失败-
guess
是一个字符串,guess
是一个整数,不能相加。依定义,Iterables是集合。int
变量不是集合;它是单个项目。什么是word
?它是可计算的吗?无论您迭代的是什么整数变量,都应该替换为范围(整数值)
,而不仅仅是整数值
。我想我们需要查看for
循环中使用的变量的最后赋值。@RobertHarvey:“依定义,Iterables是集合”?大多数集合确实倾向于可编辑,但这两个概念是截然不同的。@NPE:我不是python专家,所以我可能是把术语弄错了。我的观点是OP需要考虑错误消息告诉他什么。