如何用python将图片从服务器发送到客户端

我是python新手，我不知道我的代码有什么问题：

我设置了一个客户端和一个服务器（都在本地主机上），服务器拍摄了一个快照，并假设将其发送到保存在某个文件夹中的客户端，这一切都发生了，但JPG文件没有正确打开图片，而是说它不支持文件格式：\

守则：

# This reads all the bytes in the file 
print(myfile.read())

# this will read nothing since the file cursor is already at the end of the file. 
client_socket.send(myfile.read())

clientFile.py

import socket

# set up a socket connection object
my_socket = socket.socket()
# make the socket connect to a certain ip&port
my_socket.connect(("127.0.0.1", 8821))

data = ''

while data != 'EXIT':
    message = input('enter a message to send to the server \n')
    # send the server what to do (in this case take a snapshot)
    my_socket.send(message.encode())
    
    data = my_socket.recv(1024).decode()
   
    if data == 'snapshot has been taken':
        # recieve the file's byte length from the server ( for example: 2000000 bytes => 7 length)
        data = my_socket.recv(1).decode()
        
        sizeLength = int(data) % 10
        # recieve the size of the file picture
        data = my_socket.recv(sizeLength).decode()
        size = int(data)

        # recieve the file in binary
        picture = my_socket.recv(size)
        # trying to write the file :\
        myfile = open(r'C:\test\client\screen.jpg', 'wb')
        myfile.write(picture)
        myfile.close()
else:
    print('closing the socket')
    my_socket.close()

server.py

    import socket
    import datetime
    import glob
    import os
    import pyautogui
    import subprocess
    
    server_socket = socket.socket()
    # accepting a socket from which client (0.0.0.0) means everyone
    server_socket.bind(("0.0.0.0", 8821))
    server_socket.listen()
    # accept sockets and recieve socket and client ip&port as tuples
    (client_socket, client_address) = server_socket.accept()
    
    # data = client_socket.recv(1024).decode()
    data = ''
    while data != 'EXIT':
    .
    .
    .
        elif data == 'SNAPSHOT':
            #snapshot saved succesfully !
            image = pyautogui.screenshot()
            image.save(r'C:\test\screen.jpg') 

            # file stats (size and stuff)
            picStats = os.stat(r'C:\test\screen.jpg')
            
            picSize = picStats.st_size
            picLength = len(str(picSize))
          
            
            myfile = open(r'C:\test\screen.jpg', 'rb')
            print(myfile.read())
            reply = 'snapshot has been taken'
            # make the client prepere for the picture to be send
            client_socket.send(reply.encode())
            # send the picture length
             client_socket.send(str(picLength).encode())
            # send the picture size 
            client_socket.send(str(picSize).encode())
            client_socket.send(myfile.read())
            
.
.
.
#closing sockets eventually ...
             

我想我错过了一些东西。。。

---

谢谢

我对代码有一个问题：

# This reads all the bytes in the file 
print(myfile.read())

# this will read nothing since the file cursor is already at the end of the file. 
client_socket.send(myfile.read())

---

将字节设置为内部对象

file\u bytes=myfile.read（）

或在读取之间重置光标

myfile.seek（0）

在编辑器中打开文件（也支持以十六进制显示信息的编辑器），并查看发送文件前后的差异。特别是，我猜您对

recv

的调用包含的数据比您预期的要多，或者您使用的大小信息有误（一方面是以字符串形式发送的，另一方面是以单字节（？）形式读取的）。请编辑您问题中的代码，使其成为一个-尤其是删除这些。。。节并使其可运行。任何人都应该能够将代码复制/粘贴到两个文件中，而无需添加任何内容，运行它即可看到与您相同的结果。。您的代码不限于发送JPEG文件，您应该能够发送包含ascii内容的文件-我要做的第一件事是检查接收端是否获得了正确的文件大小。另外，您应该允许接收端接收的字节数少于完整长度，并将它们保存到文件中，然后等待剩余的字节数。您看过多处理模块了吗？这些问题都在那里解决了。你是一个传奇人物！谢谢这样愚蠢的错误