Python Seaborn-将x轴移动到顶部

我正在绘制以下数据集

data = {'Surface':[0, -50, -100, -250, -600], 'Left':[0, 0, 0, 10, 50], 'Front':[0, 0, 5, 15, 90]} 

这是一个负值数据集，因此我尝试将x轴移动到绘图的顶部，而不是正常的底部轴

现在的情节是这样的：

数据集和代码如下所示：

import seaborn as sns
import pandas as pd
import matplotlib.pyplot as plt

# initialise dataframe 
data = {'Surface':[0, -50, -100, -250, -600], 'Left':[0, 0, 0, 10, 50], 'Front':[0, 0, 5, 15, 90]} 

# Creates pandas DataFrame. 
df = pd.DataFrame(data)

#Plotting
g = sns.PairGrid(df, y_vars=["Surface"], x_vars=["Left", "Front"], height=4)
g.map(plt.scatter, color=".3")
g.map(sns.lineplot)

#Move X Axis to top
g.invert_yaxis()
g.xaxis.set_ticks_position("top")

我知道matplotlib中有一个选项，但在seaborn中尝试它会导致错误

AttributeError: 'PairGrid' object has no attribute 'xaxis'

---

我不确定这是最干净的方式，但它是有效的：

import seaborn as sns
import pandas as pd
import matplotlib.pyplot as plt

# initialise dataframe 
data = {'Surface':[0, -50, -100, -250, -600], 'Left':[0, 0, 0, 10, 50], 'Front':[0, 0, 5, 15, 90]} 

# Creates pandas DataFrame. 
df = pd.DataFrame(data)

#Plotting
g = sns.PairGrid(df, y_vars=["Surface"], x_vars=["Left", "Front"], height=4)
g.map(plt.scatter, color=".3")
g.map(sns.lineplot)

#Move X Axis to top
g.axes[0][0].invert_yaxis()
for ax in g.axes[0]:
    ax.xaxis.tick_top()
    ax.xaxis.set_label_position('top')
    ax.spines['bottom'].set_visible(False)
    ax.spines['top'].set_visible(True)

---

如上所述，链接文章的可能重复并不能解决问题。它的语法完全相同。您只需要分别拾取每个轴。检查下面的答案=）非常感谢。我不知道您需要单独指定轴

import seaborn as sns
import pandas as pd
import matplotlib.pyplot as plt

# initialise dataframe 
data = {'Surface':[0, -50, -100, -250, -600], 'Left':[0, 0, 0, 10, 50], 'Front':[0, 0, 5, 15, 90]} 

# Creates pandas DataFrame. 
df = pd.DataFrame(data)

#Plotting
g = sns.PairGrid(df, y_vars=["Surface"], x_vars=["Left", "Front"], height=4)
g.map(plt.scatter, color=".3")
g.map(sns.lineplot)

#Move X Axis to top
g.axes[0][0].invert_yaxis()
for ax in g.axes[0]:
    ax.xaxis.tick_top()
    ax.xaxis.set_label_position('top')
    ax.spines['bottom'].set_visible(False)
    ax.spines['top'].set_visible(True)