Python 蟒蛇水果机

我正在为一台水果机编写一个代码，它以随机方式选择符号，却无法找出我的错误所在。代码如下：

import random

credit  = 100

def roll(credit):

    sym1 = random.choice(symbols)
    sym2 = random.choice(symbols)
    sym3 = random.choice(symbols)
    print("---Symbols---")
    print(sym1, sym2, sym3, "\n")
    if (sym1 == sym2 or sym1 == sym3 or sym2 == sym3) and not(sym1 == sym2 == sym3):
        print("Winner! +50p")
        credit += 50
        return credit

    elif (sym1 == sym2 == sym3) and sym1 != "Bell":
        print("Winner! +£1")
        credit = credit + 100
        return credit

    elif (sym1 == sym2 == sym3) and (sym1 == "Bell"):
        print("Jackpot! +£5")
        credit = credit + 500
        return credit

    elif (sym1 == sym2 == "Skull" or sym1 == sym3 == "Skull" or sym2 == sym3 == "Skull") and not(sym1 == sym2 == sym3):
        print("Two Skulls! -£1")
        credit = credit - 100
        return credit

    elif (sym1 == sym2 == sym3) and sym1 == "Skull":
        print("Three Skulls! Lose all credit")
        credit = 0
        return credit

    else:
        print("Loser!")




symbols = ["Cherry", "Bell", "Lemon", "Orange", "Star", "Skull"]
print("You have", credit, "p", "\n")


while True:
    print("")
    play = input("Roll costs 20p. Would you like to roll? yes/no: ")
    print("")
    if play == "yes" or "y" or "Yes" or "Y":
        if credit >= 20:
            roll(credit)
            credit -= 20
            print("Credit is", credit, "p")

    else:
        print("You do not have enough money to roll!")

这里的问题是，当一个人获胜时，信用没有添加到信用变量中。然而，20便士总是被拿走。我将非常感谢您的帮助

谢谢

您可以

滚动（信用）

，但不要将值重新分配给信用。您还需要执行以下操作：

在

roll

函数中的

else

子句中添加return语句，否则游戏在第一次失败后就结束了，因为您将得到

TypeError:unsupported操作数类型for-=：'NoneType'和'int'

在

while

循环的

else

子句中添加一个break语句-否则，您必须在回答“否”后手动停止代码

完整的代码以及Farhan和Chris_Rands的建议如下：

def roll(credit):

    sym1 = random.choice(symbols)
    sym2 = random.choice(symbols)
    sym3 = random.choice(symbols)
    print("---Symbols---")
    print(sym1, sym2, sym3, "\n")
    if (sym1 == sym2 or sym1 == sym3 or sym2 == sym3) and not(sym1 == sym2 == sym3):
        print("Winner! +50p")
        credit += 50
        return credit

    elif (sym1 == sym2 == sym3) and sym1 != "Bell":
        print("Winner! +£1")
        credit = credit + 100
        return credit

    elif (sym1 == sym2 == sym3) and (sym1 == "Bell"):
        print("Jackpot! +£5")
        credit = credit + 500
        return credit

    elif (sym1 == sym2 == "Skull" or sym1 == sym3 == "Skull" or sym2 == sym3 == "Skull") and not(sym1 == sym2 == sym3):
        print("Two Skulls! -£1")
        credit = credit - 100
        return credit

    elif (sym1 == sym2 == sym3) and sym1 == "Skull":
        print("Three Skulls! Lose all credit")
        credit = 0
        return credit

    else:
        print("Loser!")
        return credit

symbols = ["Cherry", "Bell", "Lemon", "Orange", "Star", "Skull"]
print("You have", credit, "p", "\n")


while True:
 print("")
 play = input("Roll costs 20p. Would you like to roll? yes/no: ")
 print("")
 if play in {"yes","y","Yes","Y"}:
     if credit >= 20:
         credit = roll(credit)
         credit -= 20
         print("Credit is", credit, "p")

 else:
     print("You do not have enough money to roll!")
     break

---

另外

如果在{“是”、“y”、“是”、“y”}中播放：

如果你想进入else子句，这可能更适合在感谢所有人的回复：）