Python 使用列表列表中某列的公共值分组到子列表中

列表元素格式：（x0，y0，x1，y1，“字”，块号，行号，字号）

我需要按“y1”分组，其值和形式如下所示：

required = [
[
(518.1566162109375, 381.6667175292969, 537.3801879882812, 391.70867919921875, 'cost', 19, 0, 11), 
(542.1559448242188, 381.6667175292969, 556.5796508789062, 391.70867919921875, 'and', 19, 0, 12)
], 
[
(81.36001586914062, 390.6634826660156, 124.58306121826172, 400.7054443359375, 'inventory', 19, 1, 0), 
(129.35882568359375, 390.6634826660156, 167.78199768066406, 400.7054443359375, 'control,', 19, 1, 1)
]
]

请给我建议一些实现它的最佳方法。

使用&:

输出：

[
[(518.1566162109375, 381.6667175292969, 537.3801879882812, 391.70867919921875, 'cost', 19, 0, 11), (542.1559448242188, 381.6667175292969, 556.5796508789062, 391.70867919921875, 'and', 19, 0, 12)],
[(81.36001586914062, 390.6634826660156, 124.58306121826172, 400.7054443359375, 'inventory', 19, 1, 0), (129.35882568359375, 390.6634826660156, 167.78199768066406, 400.7054443359375, 'control,', 19, 1, 1)]
]

---

使用

itertools

：

import itertools
byloc = lambda x: x[3]
new_list = [list(v) for k,v in itertools.groupby(given, key=byloc)]
new_list

---

[
[(518.1566162109375, 381.6667175292969, 537.3801879882812, 391.70867919921875, 'cost', 19, 0, 11), (542.1559448242188, 381.6667175292969, 556.5796508789062, 391.70867919921875, 'and', 19, 0, 12)],
[(81.36001586914062, 390.6634826660156, 124.58306121826172, 400.7054443359375, 'inventory', 19, 1, 0), (129.35882568359375, 390.6634826660156, 167.78199768066406, 400.7054443359375, 'control,', 19, 1, 1)]
]

import itertools
byloc = lambda x: x[3]
new_list = [list(v) for k,v in itertools.groupby(given, key=byloc)]
new_list

[[(518.1566162109375,
   381.6667175292969,
   537.3801879882812,
   391.70867919921875,
   'cost',
   19,
   0,
   11),
  (542.1559448242188,
   381.6667175292969,
   556.5796508789062,
   391.70867919921875,
   'and',
   19,
   0,
   12)],
 [(81.36001586914062,
   390.6634826660156,
   124.58306121826172,
   400.7054443359375,
   'inventory',
   19,
   1,
   0),
  (129.35882568359375,
   390.6634826660156,
   167.78199768066406,
   400.7054443359375,
   'control,',
   19,
   1,
   1)]]