Python中的For和list
我对Python有一个问题。我有一个主要问题:Python中的For和list,python,Python,我对Python有一个问题。我有一个主要问题: def main(): cats = [] for x in range(1, 11): x = Cat(x) cats.append(x) listPussa = [] for x in range(1,21): x = Pussa(x) listPussa.append(x) PussaIndex = 0 for cat in
def main():
cats = []
for x in range(1, 11):
x = Cat(x)
cats.append(x)
listPussa = []
for x in range(1,21):
x = Pussa(x)
listPussa.append(x)
PussaIndex = 0
for cat in cats:
num = cat.getcatNum()
if num % 2 != 0:
for i in range(4):
cat.addPussa(listPussa[PussaIndex])
PussaIndex += 1
for cat in cats:
print cat.mixeta()
问题是,当我主要使用此功能时,要打印猫的列表:
def mixeta(self): #This is a method of the class Cat, it returns a few strings depending on how many objects Pussa has the object.
if len(self.__listPussa) is 0: #When the cat has no one, it returns that
return "Miau!", self.getcatNum(), "La llista de pusses esta buida" #The string menas that the list of Pussa is empty.
else: #When it has at least 1
listIdPussa = [] #I created a new list
for pussa in self.__listPussa: #And for every objcet Pussa in the list of Pussa
listIdPussa.append(pussa.getIdPussa()) #I save every idPussa in the list.
return "Miau!", self.getcatNum(), "El gat esta infectat. El nombre total de pusses es ", len(self.__listPussa), listIdPussa #So, at the end it returns "Meow", the number of the cat, and it says that the cat is "infected" and the total number of objects Pussa is X and each id from every object
结果必须是:
('Miau!', 1, 'El gat esta infectat. El nombre total de pusses es ', 4[0,1,2,3])
('Miau!', 2, 'La llista esta buida') # It means the list has no objects Pussa
('Miau!', 3, 'El gat esta infectat. El nombre total de pusses es ', 4[4,5,6,7])
('Miau!', 4, 'La llista esta buida')
一直走到米奥,10号
但问题是我的主要印刷品是:
('Miau!', 1, 'El gat esta infectat. El nombre total de pusses es ', 20, [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])
('Miau!', 2, 'El gat esta infectat. El nombre total de pusses es ', 20, [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])
('Miau!', 3, 'El gat esta infectat. El nombre total de pusses es ', 20, [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])
('Miau!', 4, 'El gat esta infectat. El nombre total de pusses es ', 20, [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])
所有的猫都是这样。我能做什么?这可能是因为您将
\uu listpusa
声明为类成员而不是对象成员。在这种情况下,它在Cat
的所有实例之间共享
class Cat:
__listPussa = []
def __init__(self, num):
self.num = num
每次向猫添加一些Pussa时,它们都会被添加到所有猫共享的同一变量中(yeek,猫共享它们的Pussa…:)
要实现您想要的,您需要将\uu listpusa
设置为实例成员,如下所示:
class Cat:
def __init__(self, num):
self.num = num
self.__listPussa = []
那是西班牙语的方言吗?还是加泰罗尼亚人?那它该怎么办?是的,它是加泰罗尼亚人!第一个结果是它应该做什么。因为你似乎已经从我的答案中提取了代码,你介意确保这个问题得到解决吗?@Atsuko不用担心,我们在某个时候都是新手,谢谢:)我也有这个<代码>代码def\uuuuuuu init\uuuuuuuuu(self,catNum=None,listPussa=[]):self.\uuuuuuucatnum=catNum self.\uuuuu listPussa=listPussa@Atsuko不幸的是,使用
[]
作为默认参数将不会真正起作用(请参阅)。在函数本身中将其设置为[]
。谢谢!在类init中出现了错误!!真的非常感谢!