Keras模型不'；不接受输入层

我是一个深入学习的新手，我正在尝试使用Keras在R中建立一个模型。我有20000个32x32x3图像存储在一个阵列中，用于模型训练。当我运行时：

model = keras_model_sequential()
model %>% layer_input(shape = c(32,32,3))

我得到以下错误：

Error in py_call_impl(callable, dots$args, dots$keywords) : 
TypeError: int() argument must be a string or a number, not 'Sequential'

Detailed traceback: 
File "/home/abhijit331/.virtualenvs/r-tensorflow/lib/python2.7/site-packages/tensorflow/contrib/keras/python/keras/engine/topology.py", line 1380, in Input
input_tensor=tensor)
File "/home/abhijit331/.virtualenvs/r-tensorflow/lib/python2.7/site-packages/tensorflow/contrib/keras/python/keras/engine/topology.py", line 1287, in __init__
name=self.name)
File "/home/abhijit331/.virtualenvs/r-tensorflow/lib/python2.7/site-packages/tensorflow/contrib/keras/python/keras/backend.py", line 545, in placeholder
x = array_ops.placeholder(dtype, shape=shape, name=name)
File "/home/abhijit331/.virtualenvs/r-tensorflow/lib/python2.7/site-packages/tensorflow/python/ops/array_ops.py", line 1499, in placeholder
shape = tensor_shape.as_shape(shape)
File "/home/abhijit331/.virtualenvs/r-tensorflow/lib/python2.7/site-packages/tensorflow/python/framework/tensor_shape.py", line 80

---

有人能帮我找出如何为我的模型设置输入层吗？

当使用顺序API时，您不使用

层输入功能。
您的第一层需要有一个
input\u shape
参数，该参数将充当
layer\u input
。例如：

model %>% 
  layer_dense(units = 32, input_shape = c(784)) %>%
  layer_activation('relu') %>% 
  layer_dense(units = 10) %>% 
  layer_activation('softmax')

使用函数式API时，可以使用
layer\u input
函数。看更多