如何根据R中的真或假创建直方图？

我想做的是在R中创建两个柱状图，基于海洋世界员工是否协商加薪，以及他们是否未协商加薪。有人能告诉我哪里出了问题吗。感谢您的帮助

下面是我正在使用的文本文件的一个示例

emp   received   negotiated   gender   year
#325  12.5         TRUE         F      2013
#318  5.2          FALSE        F      2013
#217  9.8          FALSE        M      2013
#223  6.8          TRUE         M      2013
#218  2.1          TRUE         F      2006
#601  13.9         FALSE        M      2006
#225  7.8          TRUE         M      2006
#281  8.5          FALSE        F      2006

以下是我目前掌握的代码：

d<-read.csv("employees.txt", header=TRUE, sep="\t")
str(d)

f1 <- mean(d$received)
f2 <- median(d$received)
f3 <- sd(d$recieved)



d$gender <- factor(d$gender, labels=c(1, 2))
pairs(d)

plot(d$received ~ d$gender)
plot(d$received ~ d$year, xlab="year", ylab="recieved")
m <- lm(d$received~d$year)
print(m)
print(f1)
print(f2)
print(f3)
abline(m)
abline(mean(d$received), 0, lty=2)


hist(d$received[d$gender ==1],breaks = 50)
dev.new()
hist(d$received[d$gender ==2],breaks = 50)
dev.new()
#hist(d$year, breaks = 50)
#dev.new()
plot(d$gender, d$received)

d数据中的
#
符号给我带来了问题

使用
#
符号

d1 <- read.table(text = "
emp   received   negotiated   gender   year
#325  12.5         TRUE         F      2013
#318  5.2          FALSE        F      2013
#217  9.8          FALSE        M      2013
#223  6.8          TRUE         M      2013
#218  2.1          TRUE         F      2006
#601  13.9         FALSE        M      2006
#225  7.8          TRUE         M      2006
#281  8.5          FALSE        F      2006", 
    header = TRUE)

但是如果没有
#
，我们会

d2 <- read.table(text = "
emp   received   negotiated   gender   year
325  12.5         TRUE         F      2013
318  5.2          FALSE        F      2013
217  9.8          FALSE        M      2013
223  6.8          TRUE         M      2013
218  2.1          TRUE         F      2006
601  13.9         FALSE        M      2006
225  7.8          TRUE         M      2006
281  8.5          FALSE        F      2006", 
    header = TRUE)

关于如何根据员工是否要求加薪创建员工加薪金额直方图的问题，请参见：

hist(d$received[d$negotiated == TRUE])
hist(d$received[d$negotiated == FALSE])

你在哪里遇到麻烦？我的猜测是“标签”与因子的基本值（编码为1和2）有一些混淆。@Frank Ok我修正了这个问题。根据员工是否要求加薪，我在创建员工加薪金额柱状图（“收到”列）时遇到了麻烦。哇，谢谢！！！如果我想创建一个基于“协商列”和性别的员工收入柱状图，它会是
hist（d$received[d$goverated==TRUE]&&[d$gender==M]）
close，它会是
hist（d$received[d$goverated==TRUE&&d$gender==F]）
，在“M”或“F”周围少放几个方括号和引号
str(d2)
'data.frame':   8 obs. of  5 variables:
 $ emp       : int  325 318 217 223 218 601 225 281
 $ received  : num  12.5 5.2 9.8 6.8 2.1 13.9 7.8 8.5
 $ negotiated: logi  TRUE FALSE FALSE TRUE TRUE FALSE ...
 $ gender    : Factor w/ 2 levels "F","M": 1 1 2 2 1 2 2 1
 $ year      : int  2013 2013 2013 2013 2006 2006 2006 2006

hist(d$received[d$negotiated == TRUE])
hist(d$received[d$negotiated == FALSE])