在缺少数据的R中添加长格式的术语
我试图在name变量下添加col1出现的次数,忽略缺少的值。它应该是2倍,但是当我使用length和count函数时,它们总是返回3在缺少数据的R中添加长格式的术语,r,R,我试图在name变量下添加col1出现的次数,忽略缺少的值。它应该是2倍,但是当我使用length和count函数时,它们总是返回3 M = data.frame( Name = c('name','name1','name','name1','name','name1'), Col1 = c(NA,1,3,4,5,NA) , Col2 = c(1,1,NA,5,8,4)) myData <- aggregate(M[,2], by = list(
M = data.frame( Name = c('name','name1','name','name1','name','name1'), Col1 = c(NA,1,3,4,5,NA) , Col2 = c(1,1,NA,5,8,4))
myData <- aggregate(M[,2],
by = list(VAR = M$Name),
FUN = function(x) c(mean = mean(x,na.rm=T), sd = sd(x,na.rm=T),n=length(x)))
myData <- do.call(data.frame, myData)
myData
#> x.n
# 3
#I want it to say 2 becuase the number only appears twice this variable.
#> x.n
# 2
M=data.frame(Name=c('Name','name1','Name','name1','Name','name1','name1'),Col1=c(NA,1,3,4,5,NA),Col2=c(1,1,NA,5,8,4))
myData x.n
# 2
尝试编辑您的函数以包含na。省略(x)
如下-
M = data.frame( Name = c('name','name1','name','name1','name','name1'), Col1 = c(NA,1,3,4,5,NA) , Col2 = c(1,1,NA,5,8,4))
myData <- aggregate(M[,2],
by = list(VAR = M$Name),
FUN = function(x) c(mean = mean(x,na.rm=T), sd = sd(x,na.rm=T),n=length(na.omit(x))))
myData <- do.call(data.frame, myData)
# VAR x.mean x.sd x.n
# 1 name 4.0 1.414214 2
# 2 name1 2.5 2.121320 2
M=data.frame(Name=c('Name','name1','Name','name1','Name','name1','name1'),Col1=c(NA,1,3,4,5,NA),Col2=c(1,1,NA,5,8,4))
myData尝试编辑您的函数以包含na。省略(x)
如下-
M = data.frame( Name = c('name','name1','name','name1','name','name1'), Col1 = c(NA,1,3,4,5,NA) , Col2 = c(1,1,NA,5,8,4))
myData <- aggregate(M[,2],
by = list(VAR = M$Name),
FUN = function(x) c(mean = mean(x,na.rm=T), sd = sd(x,na.rm=T),n=length(na.omit(x))))
myData <- do.call(data.frame, myData)
# VAR x.mean x.sd x.n
# 1 name 4.0 1.414214 2
# 2 name1 2.5 2.121320 2
M=data.frame(Name=c('Name','name1','Name','name1','Name','name1','name1'),Col1=c(NA,1,3,4,5,NA),Col2=c(1,1,NA,5,8,4))
myData这是一个tidyverse
解决方案
library(tidyverse);
M %>%
gather(k, v, -Name) %>%
filter(complete.cases(.) & k == "Col1") %>%
group_by(Name) %>%
summarise(mean = mean(v), sd = sd(v), n = n())
## A tibble: 2 x 4
# Name mean sd n
# <fct> <dbl> <dbl> <int>
#1 name 4.00 1.41 2
#2 name1 2.50 2.12 2
library(tidyverse);
M%>%
聚集(k,v,-名称)%>%
筛选器(完整的.cases(.)和k==“Col1”)%>%
分组单位(名称)%>%
总结(平均值=平均值(v),标准差=标准差(v),n=n()
##一个tibble:2x4
#名称平均值sd n
#
#1名称4.00 1.41 2
#2名称1 2.50 2.12 2
说明:我们从宽改长,通过complete.cases
删除带有NA
条目的行,并计算Name
分组条目上所需的汇总统计信息 这里有一个tidyverse
解决方案
library(tidyverse);
M %>%
gather(k, v, -Name) %>%
filter(complete.cases(.) & k == "Col1") %>%
group_by(Name) %>%
summarise(mean = mean(v), sd = sd(v), n = n())
## A tibble: 2 x 4
# Name mean sd n
# <fct> <dbl> <dbl> <int>
#1 name 4.00 1.41 2
#2 name1 2.50 2.12 2
library(tidyverse);
M%>%
聚集(k,v,-名称)%>%
筛选器(完整的.cases(.)和k==“Col1”)%>%
分组单位(名称)%>%
总结(平均值=平均值(v),标准差=标准差(v),n=n()
##一个tibble:2x4
#名称平均值sd n
#
#1名称4.00 1.41 2
#2名称1 2.50 2.12 2
说明:我们从宽改长,通过complete.cases
删除带有NA
条目的行,并计算Name
分组条目上所需的汇总统计信息 或者只使用na.省略。类似于n=length((na.ommit(x))
的方法更合适。或者只使用na.ommit
。类似于n=length((na.omit(x))
的方法更合适。