R MASS:：stepAIC-指定给steps函数参数

有人能解释为什么R中的以下代码会根据

=

或

不提供名称而给出不同的结果吗

这意味着当你打电话时

stepAIC(quine.nxt,
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  trace = TRUE,
  steps <- 6)

因此，由于指定了
scope=
和
trace=
，因此
6
的值将进入
scale=
参数。所以你写的和

stepAIC(quine.nxt,
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  trace = TRUE,
  6)

stepAIC(quine.nxt, 
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  scale = 6,
  trace = TRUE)

这和

stepAIC(quine.nxt,
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  trace = TRUE,
  6)

stepAIC(quine.nxt, 
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  scale = 6,
  trace = TRUE)

因此重要的信息是
不提供名称

这意味着当你打电话时

stepAIC(quine.nxt,
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  trace = TRUE,
  steps <- 6)

因此，由于指定了
scope=
和
trace=
，因此
6
的值将进入
scale=
参数。所以你写的和

stepAIC(quine.nxt,
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  trace = TRUE,
  6)

stepAIC(quine.nxt, 
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  scale = 6,
  trace = TRUE)

这和

stepAIC(quine.nxt,
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  trace = TRUE,
  6)

stepAIC(quine.nxt, 
  scope = list(upper = ~Eth*Sex*Age*Lrn, lower = ~1),
  scale = 6,
  trace = TRUE)

所以重要的信息是