R:循环列表
到现在为止,我已经讨论过这个问题好几次了,这次我渴望得到一个有效的解决方案。潜在的问题是我想使用R:循环列表,r,list,loops,paste,R,List,Loops,Paste,到现在为止,我已经讨论过这个问题好几次了,这次我渴望得到一个有效的解决方案。潜在的问题是我想使用paste函数循环遍历变量列表 dat <- read.csv("some file", header=TRUE) list.R <- c("IC","IG","DM","IM","IN","EN","RM") for (RO in list.R){ paste("dat$",RO,"_I", sep="")[ paste("da
paste
函数循环遍历变量列表
dat <- read.csv("some file", header=TRUE)
list.R <- c("IC","IG","DM","IM","IN","EN","RM")
for (RO in list.R){
paste("dat$",RO,"_I", sep="")[
paste("dat$",RO,"_I", sep="") ==
"Strongly disagree"] <- 1
}
或
你知道如何解决这个问题,使循环工作吗?
非常感谢您的帮助:)
(我知道在这种情况下,我也可以使用作为.numeric(levels(dat$IC_I))[dat$IC_I]
但是级别的顺序是错误的)您可以使用简单的赋值运算符来实现这一点——不需要循环(在R中通常是这样)。首先,我将构造一个示例数据框,将变量存储为字符类型而不是因子:
dat <- data.frame(id=1:2, ID_I=c("Agree", "Strongly Disagree"), IG_I=c("Strongly Disagree", "Agree"), stringsAsFactors=FALSE)
dat
# id ID_I IG_I
# 1 1 Agree Strongly Disagree
# 2 2 Strongly Disagree Agree
dat正如下面的答案所示,不要强制使用特定的方法。找到达成解决方案的最佳方式。
get(paste("dat$",RO,"_I", sep=""))
dat <- data.frame(id=1:2, ID_I=c("Agree", "Strongly Disagree"), IG_I=c("Strongly Disagree", "Agree"), stringsAsFactors=FALSE)
dat
# id ID_I IG_I
# 1 1 Agree Strongly Disagree
# 2 2 Strongly Disagree Agree
cols <- c("ID_I", "IG_I")
dat[,cols][dat[,cols] == "Strongly Disagree"] <- 1
dat
# id ID_I IG_I
# 1 1 Agree 1
# 2 2 1 Agree