R代码:如何根据其他变量的多个条件生成变量
我有一个初学者R用户: 这是我的数据集R代码:如何根据其他变量的多个条件生成变量,r,R,我有一个初学者R用户: 这是我的数据集 factor1 <- c(1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8,8,9, 9, 10, 10) factor2 <- c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,16,17, 18, 19, 20) factor3 <- c("a", "a", "a", "a", "a", "b", "b", "b", "b", "b", "c"
factor1 <- c(1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8,8,9, 9, 10, 10)
factor2 <- c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,16,17, 18, 19, 20)
factor3 <- c("a", "a", "a", "a", "a", "b", "b", "b", "b", "b", "c", "c", "c", "c", "c", "d", "d", "d", "d", "d")
factor4 <- c(10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150,160,170, 180, 190, NA)
dataset <- data.frame(factor1, factor2, factor3, factor4)
factor1使用dplyr
library(dplyr)
dataset %>%
mutate(newvar = ifelse(factor1 > 5 &
factor2 < 19 &
(factor3=="b" | factor3=="c") &
!is.na(factor4), 1, NA))
库(dplyr)
数据集%>%
变异(newvar=ifelse(因子1>5&
系数2<19&
(系数3==“b”|系数3==“c”)&
!is.na(因子4,1,na))
在base R中,您只需执行以下操作(将我的评论升级为答案):
dataset$newvar=5&dataset$factor2<19&(dataset$factor3==“b”| dataset$factor3==“c”),“newvar”]基于多个值的多个条件生成一个新变量
这一点问题没有得到明确解决:
理想情况下,我希望指定不同的条件,因此一些观察值将是变量newvar中的值1、2、3和4,取决于其他几个变量的值
一个简单的解决方案是在
时使用case\u。与Stata的recode
类似,它允许您同时指定多个值
其工作方式如下:
newvar = case_when(
condition1 ~ target value,
condition2 ~ target value)
e、 g.var1==1~0
重要信息:每行后面都需要一个,
library(dplyr)
dataset <- mutate(dataset,
newvar = case_when(
factor1 >= 5 & factor2<19 & (factor3 =="b" | factor3 =="c") ~ 1,
factor1 == 1 ~ 2,
factor1 == 2 ~ 3,
TRUE ~ NA_real_ # This is for all other values
)) # not covered by the above.
dataset
# factor1 factor2 factor3 factor4 newvar
# 1 1 1 a 10 2
# 2 1 2 a 20 2
# 3 2 3 a 30 3
# 4 2 4 a 40 3
# 5 3 5 a 50 NA
# 6 3 6 b 60 NA
# 7 4 7 b 70 NA
# 8 4 8 b 80 NA
# 9 5 9 b 90 1
# 10 5 10 b 100 1
# 11 6 11 c 110 1
# 12 6 12 c 120 1
# 13 7 13 c 130 1
# 14 7 14 c 140 1
# 15 8 15 c 150 1
# 16 8 16 d 160 NA
# 17 9 17 d 170 NA
# 18 9 18 d 180 NA
# 19 10 19 d 190 NA
# 20 10 20 d NA NA
库(dplyr)
dataset=5&factor2或:dataset$newvar=5&dataset$factor2<19&(dataset$factor3==“b”| dataset$factor3==“c”),“newvar”]这很有效。谢谢你回答了精心设计的第一个问题,包括一个可重复的示例!很抱歉,我收到此错误:找不到函数“%>%”。您发送的代码看起来很整洁,但不起作用。请你解释一下,我安装了dplyr并设法运行了你的代码,但是出于某种原因,newvar并没有改变我正在处理的数据集中的值。你能告诉我怎么做吗?thanks@Andr如果我提供的函数返回一个新的数据集,它不会重写旧的数据集。将第一行更改为dataset%
,它应该能满足您的期望。
dataset$newvar <- NA
indx <- dataset$factor1 >= 5 & dataset$factor2 < 19 & (dataset$factor3=="b" | dataset$factor3 =="c") & !is.na(dataset$factor4)
dataset[indx, "newvar"] <- 1
newvar = case_when(
condition1 ~ target value,
condition2 ~ target value)
library(dplyr)
dataset <- mutate(dataset,
newvar = case_when(
factor1 >= 5 & factor2<19 & (factor3 =="b" | factor3 =="c") ~ 1,
factor1 == 1 ~ 2,
factor1 == 2 ~ 3,
TRUE ~ NA_real_ # This is for all other values
)) # not covered by the above.
dataset
# factor1 factor2 factor3 factor4 newvar
# 1 1 1 a 10 2
# 2 1 2 a 20 2
# 3 2 3 a 30 3
# 4 2 4 a 40 3
# 5 3 5 a 50 NA
# 6 3 6 b 60 NA
# 7 4 7 b 70 NA
# 8 4 8 b 80 NA
# 9 5 9 b 90 1
# 10 5 10 b 100 1
# 11 6 11 c 110 1
# 12 6 12 c 120 1
# 13 7 13 c 130 1
# 14 7 14 c 140 1
# 15 8 15 c 150 1
# 16 8 16 d 160 NA
# 17 9 17 d 170 NA
# 18 9 18 d 180 NA
# 19 10 19 d 190 NA
# 20 10 20 d NA NA