R中的数据表来自3列
如何转换包含3列的数据集,例如:R中的数据表来自3列,r,data.table,R,Data.table,如何转换包含3列的数据集,例如: V1 V2 V3 X AB 6 X EF 5 Y CD 7 Z EF 8 A JK 9 B LM 10 B JK 6 致: 你可以用 library(reshape2) dcast(df, V1~V2, fill=0, value.var="V3") ## V1 AB CD EF JK LM ## 1 A 0 0 0 9 0 ## 2 B 0
V1 V2 V3
X AB 6
X EF 5
Y CD 7
Z EF 8
A JK 9
B LM 10
B JK 6
致:
你可以用
library(reshape2)
dcast(df, V1~V2, fill=0, value.var="V3")
## V1 AB CD EF JK LM
## 1 A 0 0 0 9 0
## 2 B 0 0 0 6 10
## 3 X 6 0 5 0 0
## 4 Y 0 7 0 0 0
## 5 Z 0 0 8 0 0
或者使用矩阵
acast(df, V1~V2, value.var='V3', fill=0)
根据@akrun的建议,您可以使用base R:
xtabs(V3~V1+V2, df)
其中:
# V2
#V1 AB CD EF JK LM
# A 0 0 0 9 0
# B 0 0 0 6 10
# X 6 0 5 0 0
# Y 0 7 0 0 0
# Z 0 0 8 0 0
# V1 AB CD EF JK LM
#1 A 0 0 0 9 0
#2 B 0 0 0 6 10
#3 X 6 0 5 0 0
#4 Y 0 7 0 0 0
#5 Z 0 0 8 0 0
或者使用tidyr
library(tidyr)
spread(df, V2, V3, fill = 0)
其中:
# V2
#V1 AB CD EF JK LM
# A 0 0 0 9 0
# B 0 0 0 6 10
# X 6 0 5 0 0
# Y 0 7 0 0 0
# Z 0 0 8 0 0
# V1 AB CD EF JK LM
#1 A 0 0 0 9 0
#2 B 0 0 0 6 10
#3 X 6 0 5 0 0
#4 Y 0 7 0 0 0
#5 Z 0 0 8 0 0
数据
structure(list(V1 = structure(c(3L, 3L, 4L, 5L, 1L, 2L, 2L), .Label = c("A",
"B", "X", "Y", "Z"), class = "factor"), V2 = structure(c(1L,
3L, 2L, 3L, 4L, 5L, 4L), .Label = c("AB", "CD", "EF", "JK", "LM"
), class = "factor"), V3 = c(6L, 5L, 7L, 8L, 9L, 10L, 6L)), .Names = c("V1",
"V2", "V3"), class = "data.frame", row.names = c(NA, -7L))