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R中所有列的循环_R_Loops - Fatal编程技术网

R中所有列的循环

R中所有列的循环,r,loops,R,Loops,我正在尝试为所有列循环此代码,其中列名为1,2,3,4,5 MoM1 <- (Data$1-lag(Data$1)) /lag(Data$1) MoM1这是否有效: > Data 1 2 3 4 5 1 6 5 5 10 6 2 1 8 1 9 6 3 4 4 5 8 2 4 5 1 4 5 2 5 9 9 10 5 8 > y <- lapply(Data, function(x) (x-lag(x))/lag(x)) > y $`1`

我正在尝试为所有列循环此代码,其中列名为1,2,3,4,5

MoM1 <- (Data$1-lag(Data$1)) /lag(Data$1)
MoM1这是否有效:

> Data
  1 2  3  4 5
1 6 5  5 10 6
2 1 8  1  9 6
3 4 4  5  8 2
4 5 1  4  5 2
5 9 9 10  5 8
> y <- lapply(Data, function(x) (x-lag(x))/lag(x))
> y
$`1`
[1]         NA -0.8333333  3.0000000  0.2500000  0.8000000

$`2`
[1]    NA  0.60 -0.50 -0.75  8.00

$`3`
[1]   NA -0.8  4.0 -0.2  1.5

$`4`
[1]         NA -0.1000000 -0.1111111 -0.3750000  0.0000000

$`5`
[1]         NA  0.0000000 -0.6666667  0.0000000  3.0000000

> names(y) <- paste0('MoM', as.numeric(names(y)))
> y
$MoM1
[1]         NA -0.8333333  3.0000000  0.2500000  0.8000000

$MoM2
[1]    NA  0.60 -0.50 -0.75  8.00

$MoM3
[1]   NA -0.8  4.0 -0.2  1.5

$MoM4
[1]         NA -0.1000000 -0.1111111 -0.3750000  0.0000000

$MoM5
[1]         NA  0.0000000 -0.6666667  0.0000000  3.0000000

> 
>数据
1 2  3  4 5
1 6 5  5 10 6
2 1 8  1  9 6
3 4 4  5  8 2
4 5 1  4  5 2
5 9 9 10  5 8
>y y
$`1`
[1] NA-0.8333333 3.0000000.2500000.8000000
$`2`
[1] NA 0.60-0.50-0.75 8.00
$`3`
[1] NA-0.84.0-0.21.5
$`4`
[1] NA-0.1000000-0.1111111-0.3750000 0.0000000
$`5`
[1] NA 0.0000000-0.66667 0.0000000 3.0000000
>姓名(y)y
$MoM1
[1] NA-0.8333333 3.0000000.2500000.8000000
$MoM2
[1] NA 0.60-0.50-0.75 8.00
$MoM3
[1] NA-0.84.0-0.21.5
$MoM4
[1] NA-0.1000000-0.1111111-0.3750000 0.0000000
$MoM5
[1] NA 0.0000000-0.66667 0.0000000 3.0000000
> 
> Data
  1 2  3  4 5
1 6 5  5 10 6
2 1 8  1  9 6
3 4 4  5  8 2
4 5 1  4  5 2
5 9 9 10  5 8
> y <- lapply(Data, function(x) (x-lag(x))/lag(x))
> y
$`1`
[1]         NA -0.8333333  3.0000000  0.2500000  0.8000000

$`2`
[1]    NA  0.60 -0.50 -0.75  8.00

$`3`
[1]   NA -0.8  4.0 -0.2  1.5

$`4`
[1]         NA -0.1000000 -0.1111111 -0.3750000  0.0000000

$`5`
[1]         NA  0.0000000 -0.6666667  0.0000000  3.0000000

> names(y) <- paste0('MoM', as.numeric(names(y)))
> y
$MoM1
[1]         NA -0.8333333  3.0000000  0.2500000  0.8000000

$MoM2
[1]    NA  0.60 -0.50 -0.75  8.00

$MoM3
[1]   NA -0.8  4.0 -0.2  1.5

$MoM4
[1]         NA -0.1000000 -0.1111111 -0.3750000  0.0000000

$MoM5
[1]         NA  0.0000000 -0.6666667  0.0000000  3.0000000

>