R 迭代器被ddply函数忽略

在data.frame中，我试图确定由另一列汇总的某一列的各个分位数。例如，假设我想要每个

iris$物种的
iris$Petal.Length
的不同分位数

分位数的数量和值是动态的，所以最终我会尝试通过概率循环或以某种方式矢量化它。这是我的矢量化尝试，但不太管用

rm(list = ls())

require(plyr)

myDat <- iris

myProbs <- c(0, 0.15, 0.5, 1)

# This doesn't return the DF I'm looking for (where probabilities/names are identified)
petals_by_species <- ddply(myDat, "Species", summarize, Quantiles = quantile(Petal.Length, probs = myProbs))
petals_by_species

rm（list=ls（））
需要（plyr）
myDat这是一张票，来自与哈德利的单独通信：

rm(list = ls())

require(plyr)

myDat <- iris

myProbs <- c(0, 0.15, 0.5, 1)

# This doesn't return the DF I'm looking for (where probabilities/names are identified)
petals_by_species <- ddply(myDat, "Species", summarize, Quantiles = quantile(Petal.Length, probs = myProbs), probs = myProbs)
petals_by_species

rm（list=ls（））
需要（plyr）
myDat这是一张票，来自与哈德利的单独通信：

rm(list = ls())

require(plyr)

myDat <- iris

myProbs <- c(0, 0.15, 0.5, 1)

# This doesn't return the DF I'm looking for (where probabilities/names are identified)
petals_by_species <- ddply(myDat, "Species", summarize, Quantiles = quantile(Petal.Length, probs = myProbs), probs = myProbs)
petals_by_species

rm（list=ls（））
需要（plyr）
myDat
rm(list = ls())

require(plyr)

myDat <- iris

myProbs <- c(0, 0.15, 0.5, 1)

# This doesn't return the DF I'm looking for (where probabilities/names are identified)
petals_by_species <- ddply(myDat, "Species", summarize, Quantiles = quantile(Petal.Length, probs = myProbs), probs = myProbs)
petals_by_species