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R 将长表单拆分为行,但重复项合并为以“分隔”分隔的字符串&引用;?_R_Dplyr_Reshape2 - Fatal编程技术网

R 将长表单拆分为行,但重复项合并为以“分隔”分隔的字符串&引用;?

R 将长表单拆分为行,但重复项合并为以“分隔”分隔的字符串&引用;?,r,dplyr,reshape2,R,Dplyr,Reshape2,假设我有一个要拆分成行的数据帧 temp = data.frame ( group=c('a','b','c'), fruits = c('apple', 'orange', 'none'), days=c('mon','tues','wed') ) reshape2::dcast(temp , days ~ group, value.var=c ( "fruits") ) days a b c 1 mon apple <NA>

假设我有一个要拆分成行的数据帧

temp = data.frame ( group=c('a','b','c'), fruits = c('apple', 'orange', 'none'), days=c('mon','tues','wed') )
reshape2::dcast(temp , days ~ group, value.var=c ( "fruits") )
  days     a      b    c
1  mon apple   <NA> <NA>
2 tues  <NA> orange <NA>
3  wed  <NA>   <NA> none
铸造将失败,只显示总数。我真正想要的是这样的东西

 days     a      b    c
1  mon apple;orange   <NA> <NA>
2 tues  <NA> orange <NA>
3  wed  <NA>   <NA> none
a、b、c天
1个月苹果;橙色
2星期二橙色
3个星期三没有

谢谢

试试这个
tidyverse
解决方案。您可以使用
paste0()
聚合数据,以获得适当的结构,以便转换为宽格式:

library(tidyverse)
#Code
temp %>%
  group_by(group,days) %>%
  summarise(fruits=paste0(fruits,collapse = ';')) %>%
  pivot_wider(names_from = group,values_from=fruits)
输出:

# A tibble: 3 x 4
  days  a            b      c    
  <chr> <chr>        <chr>  <chr>
1 mon   apple;orange NA     NA   
2 tues  NA           orange NA   
3 wed   NA           NA     none 
#一个tible:3 x 4
a、b、c天
1个月苹果;橙色钠钠
2星期二橙色NA
3星期三无

太好了,谢谢!我还使用了两步解决方案,第一步是用浆糊折叠,但你的解决方案更干净。
# A tibble: 3 x 4
  days  a            b      c    
  <chr> <chr>        <chr>  <chr>
1 mon   apple;orange NA     NA   
2 tues  NA           orange NA   
3 wed   NA           NA     none