如何检测数据帧列中的异常值？在R
我有一个数据帧，假设：如何检测数据帧列中的异常值？在R,r,dataframe,outliers,R,Dataframe,Outliers,我有一个数据帧，假设： names<-c("a","a","a","a","a","b","b","b","b","b","c","c","c","c","c","c","c","c") var1<-c(0.942999593,0.935507266,0.973589623,0.969415912,0.95230801,0.935507266,0.888740961,0.91750551,0.944482672,0.945468585,1.457579147,0.922206277,
names<-c("a","a","a","a","a","b","b","b","b","b","c","c","c","c","c","c","c","c")
var1<-c(0.942999593,0.935507266,0.973589623,0.969415912,0.95230801,0.935507266,0.888740961,0.91750551,0.944482672,0.945468585,1.457579147,0.922206277,0.941511433,0.954724791,0.941014244,0.941511433,0.941511433,1.50511433)
var2<-c(-0.012678088,0.014313763,0.001138275,-0.020568206,0.012987126,0.001217192,0.03360358,0.009758172,0.015066932,-0.037879492,0.020471157,0.010738162,0.010952531,0.019377213,0.027140572,0.031116892,-0.018530676,-8.90E-05)
as.data.frame(cbind(names,var1,var2))->df
names以下是如何为var1执行此操作：
quantiles<-tapply(var1,names,quantile)
minq <- sapply(names, function(x) quantiles[[x]]["25%"])
maxq <- sapply(names, function(x) quantiles[[x]]["75%"])
var1[var1<minq | var1>maxq] <- NA
quantiles您可以通过变量name
在df
上使用split（）
，并检测您的外地人（无论您如何定义）。@JuliánUrbano:怎么可能不呢？她要的是分位数，而不是绝对数字values@CarlWitthoft对..没读对；）我想说的是，但这更干净（注意方便的方法minq
与级别匹配）。