R 在多个列中拆分完整地址列

我有一个具有以下列结构的数据帧（总共超过1000行）：

该列包含位置、街道、门牌号、邮政编码、城市和国家。我想用R将列addressfull拆分为多个列，例如：

street        house number      zip       city      country
molengraaf    20                1689 GL   Utrecht   Netherlands
winkellaan    67                5788 BG   Amsterdam Netherlands
vermeerstraat 18                0932 DC   Rotterdam Netherlands
na            na                na        na        na
Zandhorstlaan 122               0823 GT   Ochtrup   Germany

我已经阅读了tidyr和stringr文档。我可以看到（通过“）”、“|从位置x”和“，”进行拆分的模式。但我无法找到将列拆分为多个列的正确代码

---

有人能帮我吗

对于基本R方法，您可以使用

sub

对其进行强制：

df$steet <- sub("^(\\S+)\\s+.*$", "\\1", df$adressfull)
df$`house number` <- sub("^\\S+\\s+(\\d+).*$", "\\1", df$adressfull)
df$zip <- sub("^\\S+\\s+\\d+,\\s*(\\d+\\s+[A-Z]+).*$", "\\1", df$adressfull)
df$city <- sub("^.*?(\\S+),\\s*\\S+$", "\\1", df$adressfull)
df$country <- sub("^.*,\\s*(\\S+)$", "\\1", df$adressfull)
df

                                   adressfull      steet house number     zip
1 molengraaf 20, 1689 GL Utrecht, Netherlands molengraaf           20 1689 GL
     city     country
1 Utrecht Netherlands

---

df$steet这将是解决问题的一种简单方法：

library(tidyverse)
df <- structure(list(addressfull = structure(c(3L, 5L, 4L, 2L, 1L), .Label = c("POINT (2.900824999999923 34.3175721)||DEF_84||Zandhorstlaan 122, 0823 GT Ochtrup, Germany||17||map", 
                                                                               "POINT(2.915206183 24.315583523)||DEF_32||--||13||map", "POINT(3.124537653 32.179354012)||DEF_32||molengraaf 20, 1689 GL Utrecht, Netherlands||15||map", 
                                                                               "POINT(3.124537653 32.179354012)||DEF_32||vermeerstraat 18, 0932 DC Rotterdam, Netherlands||11||map", 
                                                                               "POINT(3.124537680 32.179354014)||DEF_32||winkellaan 67, 5788 BG Amsterdam, Netherlands||13||map"
), class = "factor")), class = "data.frame", row.names = c(NA, 
                                                           -5L))



df %>% separate(addressfull, sep = "\\|\\|", into = c("Coords", "DEF", "ADDRESS"),extra = "drop") %>% 
  select(ADDRESS) %>% 
  separate(ADDRESS, sep = ",", into = c("street", "city", "country")) %>% 
  separate(street, sep = "(?= \\d)", into = c("street", "house_number")) %>% 
  separate(city, sep = "(?<=[A-Z][A-Z])", into = c("zip", "city"))
#> Warning: Expected 3 pieces. Missing pieces filled with `NA` in 1 rows [4].
#> Warning: Expected 2 pieces. Missing pieces filled with `NA` in 1 rows [4].
#>          street house_number      zip       city      country
#> 1    molengraaf           20  1689 GL    Utrecht  Netherlands
#> 2    winkellaan           67  5788 BG  Amsterdam  Netherlands
#> 3 vermeerstraat           18  0932 DC  Rotterdam  Netherlands
#> 4            --         <NA>     <NA>       <NA>         <NA>
#> 5 Zandhorstlaan          122  0823 GT    Ochtrup      Germany

库（tidyverse）
df%separate（addressfull，sep=“\\\\\\\\\\\\\\”，into=c（“坐标”、“定义”、“地址”），extra=“drop”）%>%
选择（地址）%>%
分开（地址，sep=“，”，进入=c（“街道”、“城市”、“国家”））%>%
分开（街道，sep=“（？=\\d）”，进入=c（“街道”，“房屋号”））%>%
分离（城市，sep=“（？A
stringr
解决方案如下：

addresssplit <- data.frame(
  street = str_extract(addressfull$addressfull, "(?<=DEF_\\d{2}\\|\\|)\\w+\\b"),
  number = str_extract(addressfull$addressfull, "\\d{1,}(?=,)"),
  zip = str_extract(addressfull$addressfull, "(?<=\\s)\\d{4}\\s[A-Z]{2}"),
  city = str_extract(addressfull$addressfull, "(?<=\\d{4}\\s[A-Z]{2}\\s)\\w+"),
  country = str_extract(addressfull$addressfull, "(?<=[a-z]\\b,\\s)\\w+\\b")
)

addresssplit欢迎来到StackOverflow！请阅读有关和如何提供帮助的信息。这将使其他人更容易帮助您。查看
tidyr
separate（）
df <- data.frame(adressfull=c("molengraaf 20, 1689 GL Utrecht, Netherlands"),
                 stringsAsFactors=FALSE)

text <- "POINT(3.124537653 32.179354012)||DEF_32||molengraaf 20, 1689 GL Utrecht, Netherlands||15||map"
addresfull <- unlist(strsplit(text, "\\|\\|"))[3]
addresfull

[1] "molengraaf 20, 1689 GL Utrecht, Netherlands"

library(tidyverse)
df <- structure(list(addressfull = structure(c(3L, 5L, 4L, 2L, 1L), .Label = c("POINT (2.900824999999923 34.3175721)||DEF_84||Zandhorstlaan 122, 0823 GT Ochtrup, Germany||17||map", 
                                                                               "POINT(2.915206183 24.315583523)||DEF_32||--||13||map", "POINT(3.124537653 32.179354012)||DEF_32||molengraaf 20, 1689 GL Utrecht, Netherlands||15||map", 
                                                                               "POINT(3.124537653 32.179354012)||DEF_32||vermeerstraat 18, 0932 DC Rotterdam, Netherlands||11||map", 
                                                                               "POINT(3.124537680 32.179354014)||DEF_32||winkellaan 67, 5788 BG Amsterdam, Netherlands||13||map"
), class = "factor")), class = "data.frame", row.names = c(NA, 
                                                           -5L))



df %>% separate(addressfull, sep = "\\|\\|", into = c("Coords", "DEF", "ADDRESS"),extra = "drop") %>% 
  select(ADDRESS) %>% 
  separate(ADDRESS, sep = ",", into = c("street", "city", "country")) %>% 
  separate(street, sep = "(?= \\d)", into = c("street", "house_number")) %>% 
  separate(city, sep = "(?<=[A-Z][A-Z])", into = c("zip", "city"))
#> Warning: Expected 3 pieces. Missing pieces filled with `NA` in 1 rows [4].
#> Warning: Expected 2 pieces. Missing pieces filled with `NA` in 1 rows [4].
#>          street house_number      zip       city      country
#> 1    molengraaf           20  1689 GL    Utrecht  Netherlands
#> 2    winkellaan           67  5788 BG  Amsterdam  Netherlands
#> 3 vermeerstraat           18  0932 DC  Rotterdam  Netherlands
#> 4            --         <NA>     <NA>       <NA>         <NA>
#> 5 Zandhorstlaan          122  0823 GT    Ochtrup      Germany

addresssplit <- data.frame(
  street = str_extract(addressfull$addressfull, "(?<=DEF_\\d{2}\\|\\|)\\w+\\b"),
  number = str_extract(addressfull$addressfull, "\\d{1,}(?=,)"),
  zip = str_extract(addressfull$addressfull, "(?<=\\s)\\d{4}\\s[A-Z]{2}"),
  city = str_extract(addressfull$addressfull, "(?<=\\d{4}\\s[A-Z]{2}\\s)\\w+"),
  country = str_extract(addressfull$addressfull, "(?<=[a-z]\\b,\\s)\\w+\\b")
)

addresssplit
         street number     zip      city     country
1    molengraaf     20 1689 GL   Utrecht Netherlands
2    winkellaan     67 5788 BG Amsterdam Netherlands
3 vermeerstraat     18 0932 DC Rotterdam Netherlands
4          <NA>   <NA>    <NA>      <NA>        <NA>
5 Zandhorstlaan    122 0823 GT   Ochtrup     Germany

addressfull <- structure(list(addressfull = structure(c(3L, 5L, 4L, 2L, 1L), .Label = c("POINT (2.900824999999923 34.3175721)||DEF_84||Zandhorstlaan 122, 0823 GT Ochtrup, Germany||17||map", 
                                                                                    "POINT(2.915206183 24.315583523)||DEF_32||--||13||map", "POINT(3.124537653 32.179354012)||DEF_32||molengraaf 20, 1689 GL Utrecht, Netherlands||15||map", 
                                                                                    "POINT(3.124537653 32.179354012)||DEF_32||vermeerstraat 18, 0932 DC Rotterdam, Netherlands||11||map", 
                                                                                    "POINT(3.124537680 32.179354014)||DEF_32||winkellaan 67, 5788 BG Amsterdam, Netherlands||13||map"
), class = "factor")), class = "data.frame", row.names = c(NA, 
                                                           -5L))