嵌套的if/else if基于多个列值-R
目标是根据多个条件填充一个新列(df$final.count)。下面是一个示例数据框:嵌套的if/else if基于多个列值-R,r,R,目标是根据多个条件填充一个新列(df$final.count)。下面是一个示例数据框: structure(list(item = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L), .Label = c("a", "b"), class = "factor"), raw.count = c(16, 300, 203, 6, 5, 40, 20, 16, 300, 203), loc = structure(c(4L, 2L, 2L,
structure(list(item = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L,
2L, 2L, 2L), .Label = c("a", "b"), class = "factor"), raw.count = c(16,
300, 203, 6, 5, 40, 20, 16, 300, 203), loc = structure(c(4L,
2L, 2L, 2L, 2L, 3L, 3L, 4L, 2L, 3L), .Label = c(" ", "in", "out",
"NA"), class = "factor"), side = structure(c(4L, 2L, 3L, 2L,
3L, 4L, 3L, 4L, 2L, 4L), .Label = c("F", "L", "R", "NA"), class = "factor"),
recount = c(15, NA, NA, 7, NA, NA, 16, 15, NA, NA), final.count = c(NA_real_,
NA_real_, NA_real_, NA_real_, NA_real_, NA_real_, NA_real_,
NA_real_, NA_real_, NA_real_), EXPECTED = c(15, 60, 120,
7, 5, 40, 16, 15, 300, 203)), row.names = c(NA, 10L), class = "data.frame")
目标是根据影响多个列的以下条件填充新列(df$final.count):
case\u when()
,它会变得更可读。。您还可以松开的
library( dplyr )
df %>%
mutate( final.cond = case_when(
!is.na( recount ) ~ recount,
item == "a" & raw.count > 10 & loc == "in" & side == "L" ~ 0.2 * raw.count,
item == "a" & raw.count > 10 & loc == "in" & side == "R" ~ 0.6 * raw.count,
raw.count <= 10 ~ raw.count,
loc == "out" ~ raw.count,
TRUE ~ as.numeric(NA)
))
库(dplyr)
df%>%
突变(final.cond=情况_)(
!is.na(重新计票)~重新计票,
item==“a”&raw.count>10&loc==“in”&side==“L”~0.2*raw.count,
item==“a”&raw.count>10&loc==“in”&side==“R”~0.6*raw.count,
raw.count我不确定您的逻辑是否正确,但您在所有df$final.count
中以及在最后两种情况下的raw.count
中都缺少I
。这是一个非常可读的解决方案,它通过一些调整解决了我的问题。还必须将最后一行更改为TRUE~as.numeric(NA)
library( dplyr )
df %>%
mutate( final.cond = case_when(
!is.na( recount ) ~ recount,
item == "a" & raw.count > 10 & loc == "in" & side == "L" ~ 0.2 * raw.count,
item == "a" & raw.count > 10 & loc == "in" & side == "R" ~ 0.6 * raw.count,
raw.count <= 10 ~ raw.count,
loc == "out" ~ raw.count,
TRUE ~ as.numeric(NA)
))