R 使用na.spline()和case_when()按组插值和外推
我有一些日期丢失,我想插值和外推每个组内的值,即使我只有一个值可用R 使用na.spline()和case_when()按组插值和外推,r,dataframe,dplyr,zoo,R,Dataframe,Dplyr,Zoo,我有一些日期丢失,我想插值和外推每个组内的值,即使我只有一个值可用 #create an example library(zoo) library(tidyverse) df <- data.frame(a = c("group1","group1","group1","group1","group2","group2","group2","
#create an example
library(zoo)
library(tidyverse)
df <- data.frame(a = c("group1","group1","group1","group1","group2","group2","group2","group2","group3","group3"), b = c(1,2,NA,4,1,NA,NA,NA,NA,NA))
a b
1 group1 1
2 group1 2
3 group1 NA
4 group1 4
5 group2 1
6 group2 NA
7 group2 NA
8 group2 NA
9 group3 NA
10 group3 NA
首先,我尝试按组使用na.spline
df %>% group_by(a) %>% mutate(b_interpolated = na.spline(b, na.rm = FALSE))
告诉我这个错误:
Error: Problem with `mutate()` input `test`.
x zero non-NA points
ℹ Input `test` is `na.spline(b, na.rm = FALSE)`.
ℹ The error occurred in group 3: a = "group3".
所以我尝试在任何值可用时使用na.spline
#Interpolate and extrapolate test
test <- df %>% group_by(a) %>% mutate(test = case_when(all(is.na(b)) == TRUE ~ "empty",
all(is.na(b)) == FALSE ~ "ok"))
如果使用na.approx,则无法推断group2,因为只有一个值
df %>% group_by(a) %>% mutate(b_interpolated = na.approx(b, na.rm = FALSE, rule = 2))
a b b_interpolated
<chr> <dbl> <dbl>
1 group1 1 1
2 group1 2 2
3 group1 NA 3
4 group1 4 4
5 group2 1 1
6 group2 NA NA
7 group2 NA NA
8 group2 NA NA
9 group3 NA NA
10 group3 NA NA
df%>%group_by(a)%>%mutate(b_interpolated=na.近似值(b,na.rm=FALSE,rule=2))
a b_插值
1组1
2组1 2
3组1 NA 3
4组1 4 4
5组2 1
6组2 NA NA
7第2组不适用
8组2 NA NA
9组3 NA NA
10组3 NA NA
我不明白为什么在给出错误时使用case\u,我肯定我遗漏了一些东西…这看起来像是na.spline的错误。用这个来解决它 对于na.approx,我们使用na.fill在开始和结束时将数据扩展到na。na.fill的第二个参数是一个3向量,它给出了左端、内部NAs和右端的替换规则。它可以循环使用,因此我们可以省略右端
na_spline <- function(x) if (all(is.na(x))) NA else na.spline(x, na.rm = FALSE)
na_approx <- function(x) na.fill(na.approx(x, na.rm = FALSE), c("extend", NA))
df %>%
group_by(a) %>%
mutate(spline = na_spline(b), approx = na_approx(b)) %>%
ungroup
na_样条线%
变异(样条曲线=na_样条曲线(b),近似值=na_近似值(b))%>%
解组
给予:
# A tibble: 10 x 4
a b spline approx
<chr> <dbl> <dbl> <dbl>
1 group1 1 1 1
2 group1 2 2 2
3 group1 NA 3 3
4 group1 4 4 4
5 group2 1 1 1
6 group2 NA 1 1
7 group2 NA 1 1
8 group2 NA 1 1
9 group3 NA NA NA
10 group3 NA NA NA
#一个tible:10 x 4
b样条近似
1组1
2组1 2 2
3组1 NA 3 3
4组1 4 4
5组2 1
6组2 NA 1
7组2 NA 1
8组2 NA 1
9第3组不适用
10第3组不适用
df %>% group_by(a) %>% mutate(b_interpolated = na.approx(b, na.rm = FALSE, rule = 2))
a b b_interpolated
<chr> <dbl> <dbl>
1 group1 1 1
2 group1 2 2
3 group1 NA 3
4 group1 4 4
5 group2 1 1
6 group2 NA NA
7 group2 NA NA
8 group2 NA NA
9 group3 NA NA
10 group3 NA NA
na_spline <- function(x) if (all(is.na(x))) NA else na.spline(x, na.rm = FALSE)
na_approx <- function(x) na.fill(na.approx(x, na.rm = FALSE), c("extend", NA))
df %>%
group_by(a) %>%
mutate(spline = na_spline(b), approx = na_approx(b)) %>%
ungroup
# A tibble: 10 x 4
a b spline approx
<chr> <dbl> <dbl> <dbl>
1 group1 1 1 1
2 group1 2 2 2
3 group1 NA 3 3
4 group1 4 4 4
5 group2 1 1 1
6 group2 NA 1 1
7 group2 NA 1 1
8 group2 NA 1 1
9 group3 NA NA NA
10 group3 NA NA NA