React native 按Backspace键后从聚焦文本输入中删除状态

我有多个文本输入，我一直生成这些输入，直到函数将数组的长度设置为24。函数是在“onChangeText”方法中调用的。我还在其中设置状态，这会为状态添加一个新的输入值。向状态添加值可以很好地工作，但当用户按backspace时，如何从状态中删除它们？我想我应该使用数组来存储每个输入的值，然后识别它们，但我真的不知道怎么做

世博小吃：

}

this.state = {
  iban: [],
  text: "",
};


changeText = (text) => {
this.setState(function (previousState) {
  return {
    text: previousState.text + text,
  };
});
console.log(text);

if (this.state.iban.length >= 24) {
  return;
}

const items = [
  ...this.state.iban,
  <View
    key={Math.random()}
   
  >
    <TextInput
      onKeyPress={e => {
        if (e.nativeEvent.key === "Backspace") {
          //THE CODE WHICH SHOULD CHANGE THE STATE OF FOCUSED INPUT, IN THIS CASE DELETE A SINGLE LETTER
        }
      }}
      maxLength={1}
      
      onChangeText={text => {
        if (text === "" && this.state.iban.length !== 24) {
          const copy = this.state.iban.slice(0, -1);

          this.setState({ iban: copy });
        } else this.changeText(text);
      }}
      autoFocus={true}
    
    ></TextInput>
  </View>,
];
this.setState({ iban: items });
console.log(this.state.text);

componentDidMount() {
this.changeText();