Recursion ES6中带有返回值的递归承诺
我正在尝试(使用)递归地从GitHub获取内容。内容以递归方式获取,但输入承诺的最终结果是Recursion ES6中带有返回值的递归承诺,recursion,bluebird,es6-promise,ecmascript-6,Recursion,Bluebird,Es6 Promise,Ecmascript 6,我正在尝试(使用)递归地从GitHub获取内容。内容以递归方式获取,但输入承诺的最终结果是未定义: 获取内容的函数: _getRepoContent ( user, repo, ref, path ) { return new Promise( ( resolved, rejected ) => { this._client.repo( user + "/" + repo, ref ).contents( path, ( err, data ) => {
未定义:
获取内容的函数:
_getRepoContent ( user, repo, ref, path ) {
return new Promise( ( resolved, rejected ) => {
this._client.repo( user + "/" + repo, ref ).contents( path, ( err, data ) => {
if ( err ) {
rejected( err );
} else {
resolved( data );
}
} );
} );
}
主要递归函数:
getContentRec ( sourceDef, data ) {
var results = data || [];
return this._getRepoContent( sourceDef.user, sourceDef.repo, sourceDef.ref, sourceDef.path )
.then( ( data ) => {
let dirs = [];
results = results.concat( data );
data.forEach( ( file ) => {
if ( file.type === "dir" ) {
dirs.push( file );
}
} );
if ( dirs.length > 0 ) {
let promises = [];
dirs.forEach( ( dir ) => {
let def = {
user: sourceDef.user,
repo: sourceDef.repo,
ref: sourceDef.ref,
path: dir.path
};
promises.push( this.getContentRec( def, results ) );
} );
return Promise.all( promises );
} else {
return Promise.resolve( results );
}
} )
.catch( ( err ) => {
return Promise.reject( err );
} );
}
称之为:
getContentRec(
{
user: "nodejs",
repo: "node"
}
}).then( (data) => {
// data is undefined
})
有什么想法吗?Thx提前了很多时间 解决了问题,下面是解决方案…:
getContentRec ( sourceDef ) {
return this._getRepoContent( sourceDef.user, sourceDef.repo, sourceDef.ref, sourceDef.path )
.map( ( content ) => {
let def = {
user: sourceDef.user,
repo: sourceDef.repo,
ref: sourceDef.ref,
path: content.path
};
return content.type === "dir" ? this.getContentRec( def ) : content;
} )
.reduce( ( a, b ) => {
return a.concat( b )
}, [] );
}
注:
此解决方案使用的是bluebird,而不是纯ES6承诺。Hm,有很多事情可以简化,但我看不出有什么真正的错误。getContentRec
应该始终返回一个承诺,该承诺通过数组来实现。@Bergi,是的,您完全正确,代码可以简化为一个子集;-)这是蓝鸟,不是ES6承诺吗?是的,没有它就无法工作,编辑了答案以反映这一点。