Regex 正则表达式匹配撇号

我有以下文件：

该文件中的每一行都以一个apotrophe作为分隔符结束。我需要一个正则表达式来匹配IMD+F++：：：和分隔符（'）之间的每个撇号

我有下面的正则表达式来匹配IMD+F++：：：和下面的分隔符之间的所有文本，但是我需要一个只获取多余撇号的正则表达式

(?<=IMD\+F\+\+:::)(.*?)(?='\n)

---

（？以下.NET中的正则表达式：

(?<=IMD\+F\+\+:::.*)'(?!\r?\n)

（？使用什么正则表达式风格（即什么语言）？你想替换撇号？获取是什么意思？不确定我将在其中使用的软件更喜欢什么风格的正则表达式。替换有点不精确，我的意思是在IMD+F++：：：和最后一个之间匹配撇号。如果你希望在一个字符串中有多个匹配，你必须知道你最终将使用什么正则表达式beca使用每种口味实现这一点是不同的。
Regex regexObj = new Regex(@"(?<=IMD\+F\+\+:::.*)'(?!\r\n)");
    Match matchResults = regexObj.Match(subjectString);
    while (matchResults.Success) {
        // matched text: matchResults.Value
        // match start: matchResults.Index
        // match length: matchResults.Length
        matchResults = matchResults.NextMatch();
    } 

    "
(?<=      # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind)
   IMD       # Match the characters “IMD” literally
   \+        # Match the character “+” literally
   F         # Match the character “F” literally
   \+        # Match the character “+” literally
   \+        # Match the character “+” literally
   :::       # Match the characters “:::” literally
   .         # Match any single character that is not a line break character
      *         # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
)
'         # Match the character “'” literally
(?!       # Assert that it is impossible to match the regex below starting at this position (negative lookahead)
   \r        # Match a carriage return character
      ?         # Between zero and one times, as many times as possible, giving back as needed (greedy)
   \n        # Match a line feed character
)
"