Regex Django Url赢得'；不匹配

我有不匹配的URL模式。这是我根据Django教程改编的。这可能很简单，但我只是错过了

错误：

Page not found (404)
    Request Method: GET
    Request URL:    http://127.0.0.1:8000/sendemail/1
Using the URLconf defined in emailme.urls, Django tried these URL patterns, in this order:
    1. ^sendemail ^$ [name='index']
    2. ^sendemail ^(?P<msg_id>\d+)/$ [name='detail']
    3. ^sendemail ^(?P<msg_id>\d+)/results/$ [name='results']
    4. ^admin/
The current URL, sendemail/1, didn't match any of these.

根URL.py：

from django.conf.urls import patterns, include, url

# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    url(r'^sendemail', include('sendemail.urls')),
    # Uncomment the next line to enable the admin:
    url(r'^admin/', include(admin.site.urls)),
)

URL.py：

from django.conf.urls import patterns, url
from sendemail import views

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^(?P<msg_id>\d+)/$', views.detail, name='detail'),
    url(r'^(?P<msg_id>\d+)/results/$', views.results, name='results'))

---

您要使用的模式需要一个尾随斜杠

url(r'^(?P<msg_id>\d+)/$', views.detail, name='detail'),

url（r'^（？P\d+/$），views.detail，name='detail'），

---

您正在使用的URL，

sendmail/1

，没有。能否显示您的根URL配置？将

URL（r'^sendmail'，include（'sendmail.URL'），

更改为

URL（r'^sendmail/'，include（'sendmail.URL'），

Yep！这就解决了问题。谢谢

from django.http import HttpResponse

def index(request):
    return HttpResponse("You're at the index")

def detail(request, msg_id):
    return HttpResponse("The details of message id %s" % msg_id)

def results(request, msg_id):
    return HttpResponse("The results of message id %s" % msg_id)

url(r'^(?P<msg_id>\d+)/$', views.detail, name='detail'),