Replace 如何用特定字符串替换列的内容？

大家好

因此，我有这个表（它只是原始数据集的一个子集）：

我想用IT-Rome-兴业银行

因此，我的输出应该如下所示：

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如果您能为我们提供帮助，我们将不胜感激，谢谢您

我不明白您的要求。。 你在找这个简单的更新语句吗？ 假设您的表名为表1

UPDATE Table_1
   SET Customer = 'IT-Rome - societe generale'
 WHERE Customer like ('IT - ROME%')
GO

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在Pyspark中使用类似的

操作符：

from pyspark.sql import functions as F
from pyspark.sql.functions import col

df.withColumn("Customer", F.when(col('Customer').like('IT - Rome%')\
    , 'IT - Rome - societe generale').otherwise(col('Customer'))).show()

+----------------------------+-------+
|Customer                    |Country|
+----------------------------+-------+
|IT - Rome - societe generale|Italy  |
|DE - Berlin - BNP ParisBas  |Germany|
|IT - Rome - societe generale|Italy  |
|FR - Paris - CreditAgricole |France |
+----------------------------+-------+

我想用IT-ROME-societe generale替换Customer列中以IT-ROME开头的所有字符串？
UPDATE Table_1
   SET Customer = 'IT-Rome - societe generale'
 WHERE Customer like ('IT - ROME%')
GO

from pyspark.sql import functions as F
from pyspark.sql.functions import col

df.withColumn("Customer", F.when(col('Customer').like('IT - Rome%')\
    , 'IT - Rome - societe generale').otherwise(col('Customer'))).show()

+----------------------------+-------+
|Customer                    |Country|
+----------------------------+-------+
|IT - Rome - societe generale|Italy  |
|DE - Berlin - BNP ParisBas  |Germany|
|IT - Rome - societe generale|Italy  |
|FR - Paris - CreditAgricole |France |
+----------------------------+-------+