工厂女孩的rspec let行为

工厂女孩的rspec let行为,rspec,factory-bot,Rspec,Factory Bot,我正在尝试使用FactoryGirl为我的一个控制器规格创建一些项目: 摘录: describe ItemsController do let(:item1){Factory(:item)} let(:item2){Factory(:item)} # This fails. @items is nil because Item.all returned nothing describe "GET index" do it "should assi

我正在尝试使用FactoryGirl为我的一个控制器规格创建一些项目:

摘录:

describe ItemsController do
    let(:item1){Factory(:item)}
    let(:item2){Factory(:item)}

    # This fails. @items is nil because Item.all returned nothing
    describe "GET index" do
        it "should assign all items to @items" do
            get :index
            assigns(:items).should include(item1, item2)
        end
    end

    # This passes and Item.all returns something 
    describe "GET show" do
        it "should assign the item with the given id to @item" do
            get :show, id => item1.id 
            assigns(:item).should == item1
        end
    end
end
当我将let更改为以下内容时:

before(:each) do
    @item1 = Factory(:item)
    @item2 = Factory(:item)
end
我把@s放在变量前面,一切正常。为什么带有let的版本不起作用?我试着把let换成let!他看到了相同的行为

let(:item1) { FactoryGirl.create(:item) }
let(:item2) { FactoryGirl.create(:item) }
实际上,当您让:item1执行延迟加载时,它将在内存中创建对象,但不将其保存在数据库中

@item1 = Factory(:item)
它将在数据库中创建对象

试试这个:

describe ItemsController do
    let!(:item1){ Factory(:item) }
    let!(:item2){ Factory(:item) }

    describe "GET index" do
        it "should assign all items to @items" do
            get :index
            assigns(:items).should include(item1, item2)
        end
    end

    describe "GET show" do
        it "should assign the item with the given id to @item" do
            get :show, id => item1.id 
            assigns(:item).should == item1
        end
    end
end
如果不调用let,它将永远不会被实例化,而:let!在每次方法调用之前强制计算

或者您可以这样做:

describe ItemsController do
    let(:item1){ Factory(:item) }
    let(:item2){ Factory(:item) }

    describe "GET index" do
        it "should assign all items to @items" do
            item1, item2
            get :index
            assigns(:items).should include(item1, item2)
        end
    end

    describe "GET show" do
        it "should assign the item with the given id to @item" do
            get :show, id => item1.id 
            assigns(:item).should == item1
        end
    end
end
实际上,当您让:item1执行延迟加载时,它将在内存中创建对象,但不将其保存在数据库中

@item1 = Factory(:item)
它将在数据库中创建对象

试试这个:

describe ItemsController do
    let!(:item1){ Factory(:item) }
    let!(:item2){ Factory(:item) }

    describe "GET index" do
        it "should assign all items to @items" do
            get :index
            assigns(:items).should include(item1, item2)
        end
    end

    describe "GET show" do
        it "should assign the item with the given id to @item" do
            get :show, id => item1.id 
            assigns(:item).should == item1
        end
    end
end
如果不调用let,它将永远不会被实例化,而:let!在每次方法调用之前强制计算

或者您可以这样做:

describe ItemsController do
    let(:item1){ Factory(:item) }
    let(:item2){ Factory(:item) }

    describe "GET index" do
        it "should assign all items to @items" do
            item1, item2
            get :index
            assigns(:items).should include(item1, item2)
        end
    end

    describe "GET show" do
        it "should assign the item with the given id to @item" do
            get :show, id => item1.id 
            assigns(:item).should == item1
        end
    end
end

嗨,谢谢你的建议。这并没有解决问题。最后我的问题是我已经试过了。嗨,谢谢你的建议。这并没有解决问题。最后我的问题是我已经试过了。