Ruby on rails 将值从视图传递给辅助对象

Ruby on rails 将值从视图传递给辅助对象,ruby-on-rails,ruby-on-rails-3,view,helper,Ruby On Rails,Ruby On Rails 3,View,Helper,我有以下表格: projects users projects_users <- relational table …这意味着“@project.id”或“current_user.id”为零。在本例中,我非常确定@project.id为零,并且它实际上没有传递给助手 如果我是对的,我如何将其传递给助手? 如果我错了,有什么问题 视图: 1. <% @projects.each do |project| %> 2. <div class="project_c

我有以下表格:

projects
users
projects_users <- relational table
…这意味着“@project.id”或“current_user.id”为零。在本例中,我非常确定@project.id为零,并且它实际上没有传递给助手

如果我是对的,我如何将其传递给助手? 如果我错了,有什么问题

视图:

1.  <% @projects.each do |project| %>
2.      <div class="project_container">
3.          <% if check_if_member %>
4.              <% if project.user_id == current_user.id %>
5.                  <div class="users_project label label-success">
6.                      Owner
7.                  </div>
8.              <% else %>
9.                  <div class="not_users_project label label-info">
10.                     Member
11.                 </div>
12.             <% end %>
13.             <div class="project_name_div">
14.                 <%= link_to (project.title), project_path(project) %><br />
15.             </div>
16.         <% else %>
17.             <div class="project_name_div">
18.                 project.title <br />
19.             </div>
20.         <% end %>
21.     </div>
22. <% end %>
module ProjectsHelper
    def check_if_member
        if ProjectsUser.where("project_id = ? AND user_id = ?", @project.id, current_user.id)
            return true
        else
            return false
        end
    end
end
明确通过

def check_if_member project, user
    ProjectsUser.where("project_id = ? AND user_id = ?", project.id, user.id).count > 0
end
然后


“为nil.调用id”是在您调用@variable.id且@variable为nil时生成的。这与调用variable.id且未定义变量时不同。
def check_if_member project, user
    ProjectsUser.where("project_id = ? AND user_id = ?", project.id, user.id).count > 0
end
<% if check_if_member(project, current_user) %>