Ruby on rails 合并两个哈希

我正在使用谷歌公民信息API。它给了我两个哈希数组。我想在屏幕上打印来自这两方面的信息。散列1有一些整数作为k-v对（officialindice）。它们表示第二个散列中对应对象的索引号。如何将这两者合并？我想同时显示两个散列中的信息。也许最好用第二个数组中的索引哈希替换officialindice的值。谢谢你的建议

散列1:

{
  "name"       => "President of the United States",
  "divisionId" => "ocd-division/country:us",
  "levels" => ["country"],
  "roles" => ["headOfState", "headOfGovernment"],
  "officialIndices" => [0]
}

{
  "name" => "Barack Obama",
  "address" => [{
    "line1" => "The White House",
    "line2" => "1600 pennsylvania avenue nw",
    "city" => "washington",
    "state" => "DC",
    "zip" => "20500"
  }],
  "party" => "Democratic",
  "phones" => ["(202) 456-1111"],
  "urls" => ["http://www.whitehouse.gov/"],
  "photoUrl" => "http://www.whitehouse.gov/sites/default/files/imagecache/admin_official_lowres/administration-official/ao_image/president_official_portrait_hires.jpg",
  "channels" => [
    { "type" => "GooglePlus", "id" => "+whitehouse" },
    { "type" => "Facebook", "id" => "whitehouse" },
    { "type" => "Twitter", "id" => "whitehouse" },
    { "type" => "YouTube", "id" => "barackobama" }
  ]
}

散列2:

{
  "name"       => "President of the United States",
  "divisionId" => "ocd-division/country:us",
  "levels" => ["country"],
  "roles" => ["headOfState", "headOfGovernment"],
  "officialIndices" => [0]
}

{
  "name" => "Barack Obama",
  "address" => [{
    "line1" => "The White House",
    "line2" => "1600 pennsylvania avenue nw",
    "city" => "washington",
    "state" => "DC",
    "zip" => "20500"
  }],
  "party" => "Democratic",
  "phones" => ["(202) 456-1111"],
  "urls" => ["http://www.whitehouse.gov/"],
  "photoUrl" => "http://www.whitehouse.gov/sites/default/files/imagecache/admin_official_lowres/administration-official/ao_image/president_official_portrait_hires.jpg",
  "channels" => [
    { "type" => "GooglePlus", "id" => "+whitehouse" },
    { "type" => "Facebook", "id" => "whitehouse" },
    { "type" => "Twitter", "id" => "whitehouse" },
    { "type" => "YouTube", "id" => "barackobama" }
  ]
}

编辑**澄清一下，散列1是散列数组中的第一个散列。哈希2是哈希数组中的第一个哈希。我想用散列2替换散列1中officialIndice中的数字。这让我很困惑，因为有些药剂师有不止一个数字。希望这是有道理的

您可以使用

散列#合并

合并两个散列中的信息。但是，两者中都有重叠的键（

名称

），因此在合并之前，您需要将其重命名为哈希：

# Rename "name" to "position_name" before merging to prevent collision
hash1["position_name"] = hash1.delete("name")

merged_hash = hash1.merge(hash2)

可以与块一起使用：

foo = { "name" => "President of the United States" }
bar = { "name" => "Barack Obama" }

foo.merge(bar) { |key, old_val, new_val| {description: old_val, value: new_val} }
=> {"name"=>{:description=>"President of the United States", 
             :value=>"Barack Obama"}}

---

因此，您可以通过这种方式指定

merge

逻辑。如果您有多个具有类似逻辑的重叠键，此解决方案将有效。

合并将不起作用；如果

officialindice

有多个元素，您会怎么做

array1.each do |el1|
  el1["officials"] = el1["officialIndices"].map { |idx|
    array2[idx]
  }
  el1.delete("officialIndices")
end

---

（注意：这是破坏性的，即它将更改

array1

。如果您希望

array1

不变，我将重写。）

您说，“这些表示第二个哈希中对应对象的索引号。”什么是“对应对象”？该索引如何用于构建合并哈希？请编辑以澄清并显示示例所需的合并哈希。谢谢。那是真的，但我不是很清楚。哈希1是哈希数组中的第一个哈希。哈希2是哈希数组中的第一个哈希。我想把这两个散列中的信息合并起来。我可以通过将officialIndice插入第二个数组来实现这一点。officialIndice代表第二个散列的索引号。我建议

el1[“officialIndice”]=array2.values\u在（*el1[“officialIndice”]）

。你擅离职守了。