Ruby on rails 将curl命令转换为httparty
我试图在Mailchimp V3列表中添加带有HTTParty的合并字段,但无法将curl转换为HTTParty格式。Ruby on rails 将curl命令转换为httparty,ruby-on-rails,curl,mailchimp,Ruby On Rails,Curl,Mailchimp,我试图在Mailchimp V3列表中添加带有HTTParty的合并字段,但无法将curl转换为HTTParty格式。 工作正常的Curl请求格式: curl --request POST \ --url 'https://usxx.api.mailchimp.com/3.0/lists/17efad7sd4/merge-fields' \ --user '12:d1c1d99dr5000c63f0f73f64b88e852e-xx' \ --header 'con
工作正常的Curl请求格式:
curl --request POST \
--url 'https://usxx.api.mailchimp.com/3.0/lists/17efad7sd4/merge-fields' \
--user '12:d1c1d99dr5000c63f0f73f64b88e852e-xx' \
--header 'content-type: application/json' \
--data '{"name":"FAVORITEJOKE", "type":"text"}' \
--include
缺少错误API密钥的Httparty格式
response = HTTParty.post("https://us12.api.mailchimp.com/3.0/lists/17efad7sde/merge-fields",
:body => {
:user => '12:d1c1d99dr5000c63f0f73f64b88e852e-xx',
:data => '{"name":"FAVORITEJOKE", "type":"text"}',
:include => ''
}.to_json,
:headers => { 'Content-Type' => 'application/json' } )
我也尝试不使用include选项,但不起作用您的代码中有几个错误
- curl
是基本的身份验证用户,但您正在请求的有效负载中传递它user
- 数据是有效负载,而是将其作为有效负载中的节点传递,然后对其进行双重序列化
- 包含在那里没有意义,它不是有效负载项
HTTParty
和curl
文档,并理解它们之间的区别
HTTParty.post(
"https://us12.api.mailchimp.com/3.0/lists/17efad7sde/merge-fields",
basic_auth: { username: "12", password: "d1c1d99dr5000c63f0f73f64b88e852e-xx" },
headers: { 'Content-Type' => 'application/json' },
body: {
name: "FAVORITEJOKE",
type: "text",
}.to_json
)
感谢Simone Carletticurl->httparty converter将是史诗般的。