在Ruby中字符串是可变的吗?
在Ruby中字符串是可变的吗?按照惯例 创建一个值为“hello world”的新字符串对象在Ruby中字符串是可变的吗?,ruby,string,immutability,mutable,Ruby,String,Immutability,Mutable,在Ruby中字符串是可变的吗?按照惯例 创建一个值为“hello world”的新字符串对象 str = "hello" str << " world" str=“你好” str是的,“你好” irb(主):012:0>str.object\u id => 22269036 irb(主要):013:0>str“你好,世界” irb(主):014:0>str.object\u id => 22269036 irb(main):015:0>str=str+“世界” =>“你好,世界”
str = "hello"
str << " world"
str=“你好”
str是的,
“你好”
irb(主):012:0>str.object\u id
=> 22269036
irb(主要):013:0>str“你好,世界”
irb(主):014:0>str.object\u id
=> 22269036
irb(main):015:0>str=str+“世界”
=>“你好,世界”
irb(主):016:0>str.object\u id
=> 21462360
irb(主要):017:0>
作为补充,这种可变性的一个含义如下:
ruby-1.9.2-p0 :001 > str = "foo"
=> "foo"
ruby-1.9.2-p0 :002 > ref = str
=> "foo"
ruby-1.9.2-p0 :003 > str = str + "bar"
=> "foobar"
ruby-1.9.2-p0 :004 > str
=> "foobar"
ruby-1.9.2-p0 :005 > ref
=> "foo"
及
是的,它们是:
x = "hallo"
x[1] = "e"
p x # "hello"
+为了演示如何确定对象是否确实相同或不同,有人能向我解释一下为什么这个答案被否决了吗?
ruby-1.9.2-p0 :001 > str = "foo"
=> "foo"
ruby-1.9.2-p0 :002 > ref = str
=> "foo"
ruby-1.9.2-p0 :003 > str = str + "bar"
=> "foobar"
ruby-1.9.2-p0 :004 > str
=> "foobar"
ruby-1.9.2-p0 :005 > ref
=> "foo"
ruby-1.9.2-p0 :001 > str = "foo"
=> "foo"
ruby-1.9.2-p0 :002 > ref = str
=> "foo"
ruby-1.9.2-p0 :003 > str << "bar"
=> "foobar"
ruby-1.9.2-p0 :004 > str
=> "foobar"
ruby-1.9.2-p0 :005 > ref
=> "foobar"
ruby-1.9.2-p0 :001 > "foo" == "foo"
=> true
ruby-1.9.2-p0 :002 > "foo".object_id == "foo".object_id
=> false
ruby-1.9.2-p0 :003 > :foo == :foo
=> true
ruby-1.9.2-p0 :004 > :foo.object_id == :foo.object_id
=> true
x = "hallo"
x[1] = "e"
p x # "hello"