Ruby 如何从另一种方法中获取结果

我有一个带有子目录的目录结构：

../../../../../MY_PROJECT/TEST_A/cats/
../../../../../MY_PROJECT/TEST_B/dogs/
../../../../../MY_PROJECT/TEST_A/tigers/
../../../../../MY_PROJECT/TEST_A/elephants/

每个文件都有一个以“.sln””结尾的文件：

这些文件包含特定于其目录的信息。我想做以下工作：

在每个子目录中创建一个文件

“myfile.txt”

，并向其写入一些字符串：

../../../../../MY_PROJECT/TEST_A/cats/myfile.txt
../../../../../MY_PROJECT/TEST_B/dogs/myfile.txt
../../../../../MY_PROJECT/TEST_A/tigers/myfile.txt
../../../../../MY_PROJECT/TEST_A/elephants/myfile.txt

使用以下方法将

“.sln”

文件中的特定字符串复制到特定目录的

myfile.txt

：

def parse_sln_files
  sln_files = Dir["../../../../../MY_PROJECT/TEST_*/**/*.sln"]
  sln_files.each do |file_name|
    File.open(file_name) do |f|
      f.each_line { |line|
        if line =~ /C Source files ="..\\/                                   #"
          path = line.scan(/".*.c"/)
          puts path
        end
      }
    end
  end
end

我想这样做：

def create_myfile
  Dir['../../../../../MY_PROJECT/TEST_*/*/'].each do |dir|
    File.new File.join(dir, 'myfile.txt'), 'w+'
    Dir['../../../../../TEST/TEST_*/*/myfile.txt'].each do |path|
      File.open(path,'w+') do |f|
        f.puts "some text...."
        f.puts "some text..."
        f.puts # here I would like to return the result of parse_sln_files
      end
    end
  end
end

def parse_sln_and_store_source_files
  sln_files = Dir["../../../../../MY_PROJECT/TEST_*/**/*.sln"]
  sln_files.each do |file_name|

    #### Lets collect source file names in this array
    source_file_names = []

    File.open(file_name) do |f|
      f.each_line { |line|
        if line =~ /C Source files ="..\\/                                  #"
          path = line.scan(/".*.c"/)

          ############ Add path to array ############
          source_file_names << path
        end
      }
    end

    #### lets create `myfile.txt` in same dir as that of .sln     
    test_file = File.expand_path(File.dirname(file_name)) + "/myfile.txt"

    File.open(test_file,'w+') do |f|
        f.puts "some text...."
        f.puts "some text..."

        ##### Iterate over source file names & write to file
        source_file_names.each { |n| f.puts n }
    end

  end
end

---

关于如何表达这一点，

< p>似乎你想从VisualC++解决方案文件中读取C文件名列表，并将其存储在同一目录中的一个单独文件中。您可能需要合并代码中显示的两个循环，并执行以下操作：

def create_myfile
  Dir['../../../../../MY_PROJECT/TEST_*/*/'].each do |dir|
    File.new File.join(dir, 'myfile.txt'), 'w+'
    Dir['../../../../../TEST/TEST_*/*/myfile.txt'].each do |path|
      File.open(path,'w+') do |f|
        f.puts "some text...."
        f.puts "some text..."
        f.puts # here I would like to return the result of parse_sln_files
      end
    end
  end
end

def parse_sln_and_store_source_files
  sln_files = Dir["../../../../../MY_PROJECT/TEST_*/**/*.sln"]
  sln_files.each do |file_name|

    #### Lets collect source file names in this array
    source_file_names = []

    File.open(file_name) do |f|
      f.each_line { |line|
        if line =~ /C Source files ="..\\/                                  #"
          path = line.scan(/".*.c"/)

          ############ Add path to array ############
          source_file_names << path
        end
      }
    end

    #### lets create `myfile.txt` in same dir as that of .sln     
    test_file = File.expand_path(File.dirname(file_name)) + "/myfile.txt"

    File.open(test_file,'w+') do |f|
        f.puts "some text...."
        f.puts "some text..."

        ##### Iterate over source file names & write to file
        source_file_names.each { |n| f.puts n }
    end

  end
end

def解析和存储源文件
sln_files=Dir[”../../../../../../../MY_PROJECT/TEST.*/***.sln“]
sln_files.each do| file_name|
####让我们在此数组中收集源文件名
源文件名=[]
File.open（文件名）do | f|
f、 每条{线|
如果line=~/C Source files=“..\\/#”
路径=行扫描（/“*.c”/）
############将路径添加到数组############
源文件名太棒了！这正是我想要的！