Ruby 具有不同属性的数组的数组

我有一个这样的数组

array = [[Sat, 01 Jul 2017, 2.0],
         [Sat, 01 Jul 2017, 2.0],
         [Wed, 05 Jul 2017, 2.0],
         [Thu, 06 Jul 2017, 2.0],
         [Thu, 06 Jul 2017, 18.0],
         [Fri, 07 Jul 2017, 2.0],
         [Wed, 12 Jul 2017, 2.0],
         [Thu, 13 Jul 2017, 2.0],
         [Fri, 14 Jul 2017, 2.0],
         [Wed, 19 Jul 2017, 2.0],
         [Thu, 20 Jul 2017, 2.0],
         [Fri, 21 Jul 2017, 2.0],
         [Wed, 26 Jul 2017, 2.0],
         [Thu, 27 Jul 2017, 2.0],
         [Fri, 28 Jul 2017, 2.0]]

array = [[Sat, 01 Jul 2017, 4.0],
         [Wed, 05 Jul 2017, 2.0],
         [Thu, 06 Jul 2017, 20.0],
         [Fri, 07 Jul 2017, 2.0],
         [Wed, 12 Jul 2017, 2.0],
         [Thu, 13 Jul 2017, 2.0],
         [Fri, 14 Jul 2017, 2.0],
         [Wed, 19 Jul 2017, 2.0],
         [Thu, 20 Jul 2017, 2.0],
         [Fri, 21 Jul 2017, 2.0],
         [Wed, 26 Jul 2017, 2.0],
         [Thu, 27 Jul 2017, 2.0],
         [Fri, 28 Jul 2017, 2.0]]

我想像这样转换这个数组

array = [[Sat, 01 Jul 2017, 2.0],
         [Sat, 01 Jul 2017, 2.0],
         [Wed, 05 Jul 2017, 2.0],
         [Thu, 06 Jul 2017, 2.0],
         [Thu, 06 Jul 2017, 18.0],
         [Fri, 07 Jul 2017, 2.0],
         [Wed, 12 Jul 2017, 2.0],
         [Thu, 13 Jul 2017, 2.0],
         [Fri, 14 Jul 2017, 2.0],
         [Wed, 19 Jul 2017, 2.0],
         [Thu, 20 Jul 2017, 2.0],
         [Fri, 21 Jul 2017, 2.0],
         [Wed, 26 Jul 2017, 2.0],
         [Thu, 27 Jul 2017, 2.0],
         [Fri, 28 Jul 2017, 2.0]]

array = [[Sat, 01 Jul 2017, 4.0],
         [Wed, 05 Jul 2017, 2.0],
         [Thu, 06 Jul 2017, 20.0],
         [Fri, 07 Jul 2017, 2.0],
         [Wed, 12 Jul 2017, 2.0],
         [Thu, 13 Jul 2017, 2.0],
         [Fri, 14 Jul 2017, 2.0],
         [Wed, 19 Jul 2017, 2.0],
         [Thu, 20 Jul 2017, 2.0],
         [Fri, 21 Jul 2017, 2.0],
         [Wed, 26 Jul 2017, 2.0],
         [Thu, 27 Jul 2017, 2.0],
         [Fri, 28 Jul 2017, 2.0]]

或

或

---

不确定需要做什么。您想按日期对数组进行排序吗？…到目前为止您尝试了什么？2017年7月1日的Sat是日期对象还是字符串？如果是后者，请添加引号。我假设您希望删除每天的重复项，但无论您的目标是什么，您都应该陈述它，而不仅仅是使用示例来推断它。由于数组似乎是按日期排序的，

chunk

或

slice\u时

可能比

group\u by

更具描述性。非常感谢@mudasobwa

array.each_with_object(Hash.new(0)) do |(k, v), acc|
  acc[k] += v
end.to_a