Ruby：替换多维数组中的匹配元素？

有人能告诉我如何替换这个2D数组中的元素吗？我尝试了每种方法，包括和替换，但都无法找出哪里出了问题。提前感谢您的帮助

class Lotto

  def initialize
    @lotto_slip = Array.new(5) {Array(6.times.map{rand(1..60)})}
  end

  def current_pick
    @number = rand(1..60).to_s
    puts "The number is #{@number}."
  end

  def has_number
    #prints out initial slip
      @lotto_slip.each {|x| p x}

    #Prints slip with an "X" replacing number if  is on slip
    #Ex: @number equals 4th number on slip  --> 1, 2, 3, X, 5, 6
      @lotto_slip.each do |z|
      if z.include?(@number)
          z = "X"
          p @lotto_slip
      else
          z = z
          p @lotto_slip
      end
    end  
  end
end



test = Lotto.new
test.current_pick
test.has_number

---

让我知道这是否可行（尝试将变化从1减少到10，以便能够更轻松地进行测试）：

我在代码中看到的问题是：

• 对于这行

  @number=rand（1..60），您不需要
  到_s
  。到_s

  ，否则您将如何将数组生成的数字与实际字符串进行比较

• 您需要重新生成数组，而不是重新分配，这就是为什么我将所有代码替换为

  z.map！{| x | x=@number？'x'：x}

  基本上重新生成整个数组

---

无需对每个

进行迭代，使用
map
：

@lotto_slip = Array.new(5) {Array(6.times.map{rand(1..60)})}
#=> [[25, 22, 10, 10, 57, 17], [37, 4, 8, 52, 55, 7], [44, 30, 58, 58, 50, 19], [49, 49, 24, 31, 26, 28], [24, 18, 39, 27, 8, 54]]

@number = 24
@lotto_slip.map{|x| x.map{|x| x == @number ? 'X' : x}}
#=> [[25, 22, 10, 10, 57, 17], [37, 4, 8, 52, 55, 7], [44, 30, 58, 58, 50, 19], [49, 49, "X", 31, 26, 28], ["X", 18, 39, 27, 8, 54]]

太棒了，谢谢。我正在学习语法和正确的使用方法。我真的很感谢你的帮助，看起来。map将是下一个学习的对象。旁白：你可以写
@lotto_slip=Array.new（5）{Array.new（6）{rand（1..60）}
。
@lotto_slip = Array.new(5) {Array(6.times.map{rand(1..60)})}
#=> [[25, 22, 10, 10, 57, 17], [37, 4, 8, 52, 55, 7], [44, 30, 58, 58, 50, 19], [49, 49, 24, 31, 26, 28], [24, 18, 39, 27, 8, 54]]

@number = 24
@lotto_slip.map{|x| x.map{|x| x == @number ? 'X' : x}}
#=> [[25, 22, 10, 10, 57, 17], [37, 4, 8, 52, 55, 7], [44, 30, 58, 58, 50, 19], [49, 49, "X", 31, 26, 28], ["X", 18, 39, 27, 8, 54]]