Ruby 将seconds参数传递到方法并存储在哪里?将秒转换为字符串00:00:00

Ruby 将seconds参数传递到方法并存储在哪里?将秒转换为字符串00:00:00,ruby,timer,string-formatting,instance-variables,datetime-conversion,Ruby,Timer,String Formatting,Instance Variables,Datetime Conversion,我得到一个错误: Timer should initialize to 0 seconds time_string should display 0 seconds as 00:00:00 (FAILED - 1) Failures: 1) Timer time_string should display 0 seconds as 00:00:00 Failure/Error: @timer.seconds = 0 NoMethodError:

我得到一个错误:

Timer
  should initialize to 0 seconds
  time_string
      should display 0 seconds as 00:00:00 (FAILED - 1)

 Failures:

  1) Timer time_string should display 0 seconds as 00:00:00
     Failure/Error: @timer.seconds = 0
     NoMethodError:
       undefined method `seconds=' for #<Timer:0x007fd68b27c8d8>
我的代码:

我正在将第一个测试初始化为0,但我认为我做得不对

此外,当我在terminal ruby中的time_string方法中运行代码时,它会返回正确的时间。但我只是不知道当@timer.seconds=0或…seconds=12时如何发回


提前谢谢

class Timer def seconds@Timer=0 end def seconds=@Timer end def time\u string@Timer=time.at(@Timer.utc.strftime(“%H:%M:%S”)end
已将其清理干净。是的,我认为我原来的timer=方法设置了@timer值。但我错了。我已经按照你的建议更新了。似乎让我克服了“错误”的
未定义方法
seconds='。现在它说的论点数目不对。但是规范似乎不接受参数。明白了!将我的代码更新为
def seconds=x@timer=x end
。谢谢那是丢失的一块。我不知道可以将方法定义为seconds=。谢谢
require 'timer'

describe "Timer" do
  before(:each) do
    @timer = Timer.new
  end

 it "should initialize to 0 seconds" do
    @timer.seconds.should == 0
 end

describe 'time_string' do
 it "should display 0 seconds as 00:00:00" do
   @timer.seconds = 0
   @timer.time_string.should == "00:00:00"
end

it "should display 12 seconds as 00:00:12" do
  @timer.seconds = 12
  @timer.time_string.should == "00:00:12"
end
class Timer

  def timer=(timer  )
    @timer = timer
  end

  def seconds (x = 0)
    @timer = x
  end

  def time_string
   Time.at(@timer).utc.strftime("%H:%M:%S")
  end
 end