Ruby：将分隔符与正则表达式匹配
我试图用一个正则表达式模式来解决这个问题，即使我的测试通过了这个解决方案，我还是希望在数组中只包含Ruby：将分隔符与正则表达式匹配,ruby,regex,Ruby,Regex,我试图用一个正则表达式模式来解决这个问题，即使我的测试通过了这个解决方案，我还是希望在数组中只包含[“1”，“2”]。有更好的方法吗 内部评级法测试： s = "//;\n1;2" # when given a delimiter of ';' s2 = "1,2,3" # should read between commas s3 = "//+\n2+2" # should read between delimiter of '+' s.split(/[,\n]|[^0-9]/)
[“1”，“2”] s = "//;\n1;2" # when given a delimiter of ';'
s2 = "1,2,3" # should read between commas
s3 = "//+\n2+2" # should read between delimiter of '+'
s.split(/[,\n]|[^0-9]/)
=> ["", "", "", "", "1", "2"]
module StringCalculator
def self.add(input)
solution = input.scan(/\d+/).map(&:to_i).reduce(0, :+)
input.end_with?("\n") ? nil : solution
end
end
context 'when given a newline delimiter' do
it 'should read between numbers' do
expect(StringCalculator.add("1\n2,3")).to eq(6)
end
it 'should not end in a newline' do
expect(StringCalculator.add("1,\n")).to be_nil
end
end
context 'when given different delimiter' do
it 'should support that delimiter' do
expect(StringCalculator.add("//;\n1;2")).to eq(3)
end
end
s = "//;\n1;2" # when given a delimiter of ';'
s2 = "1,2,3" # should read between commas
s3 = "//+\n2+2" # should read between delimiter of '+'
s.split(/[,\n]|[^0-9]/)
=> ["", "", "", "", "1", "2"]
module StringCalculator
def self.add(input)
solution = input.scan(/\d+/).map(&:to_i).reduce(0, :+)
input.end_with?("\n") ? nil : solution
end
end
context 'when given a newline delimiter' do
it 'should read between numbers' do
expect(StringCalculator.add("1\n2,3")).to eq(6)
end
it 'should not end in a newline' do
expect(StringCalculator.add("1,\n")).to be_nil
end
end
context 'when given different delimiter' do
it 'should support that delimiter' do
expect(StringCalculator.add("//;\n1;2")).to eq(3)
end
end
s = "//;\n1;2" # when given a delimiter of ';'
s2 = "1,2,3" # should read between commas
s3 = "//+\n2+2" # should read between delimiter of '+'
s.split(/[,\n]|[^0-9]/)
=> ["", "", "", "", "1", "2"]
module StringCalculator
def self.add(input)
solution = input.scan(/\d+/).map(&:to_i).reduce(0, :+)
input.end_with?("\n") ? nil : solution
end
end
context 'when given a newline delimiter' do
it 'should read between numbers' do
expect(StringCalculator.add("1\n2,3")).to eq(6)
end
it 'should not end in a newline' do
expect(StringCalculator.add("1,\n")).to be_nil
end
end
context 'when given different delimiter' do
it 'should support that delimiter' do
expect(StringCalculator.add("//;\n1;2")).to eq(3)
end
end
/\d/[0-9]/\d+/s = "//;\n11;2"
s.scan(/\d+/) # => ["11", "2"]
您得到的数据看起来像以下字符串：
/1\n212//1
212
input = "//1\n212".split("\n")
delimiter = input.first[2] # => "1"
values = input.last.split(delimiter) # => ["2", "2"]
line = File.foreach('foo.txt')
delimiter = line.next[2] # => "1"
values = line.next.chomp.split(delimiter) # => ["2", "2"]
我在第一次循环时就这样做了，但问题是我需要实际读取这些字符之间的数字。我觉得我在作弊，哈哈。老实说，在
^0-90-9s=“/；\n11；2”s.split（/[^0-9]/）#=>[，，，，，，，，“11”，“2”]，。如何删除这些空字符串？字符串是否总是以//开头\n
？这是什么意思？当你要更改你的帖子时，写一个词“编辑”，然后放入新内容。不要移除第一个帖子。如果你删除了别人会认为我愚蠢的内容，希望你能理解。明白了，我对这个问题有了更多的见解@aruprakshit“1,2,3”的预期输出
？一旦我有了定界符，我就这样链接它solution=input.split（/[，\n]/）.map（&:to_i）.reduce（0，：+）
我建议尝试使用模式拆分字符串会导致解决方案过于复杂<代码>扫描\d+scanadd（）