Rust 对于带有`#From`指令的`'std:：Error:：Error`自动实现`From`失败

我收到了这个错误：

error[E0277]: `?` couldn't convert the error to `&ArchiveError`
  --> src/archive.rs:45:38
   |
42 | fn extract<R: Read + Seek>(filename: &'static str) -> Result<(), &ArchiveError> {
   |                                                       ------------------------- expected `&ArchiveError` because of this
...
45 |             ArchiveZip::new(filename)?
   |                                      ^ the trait `From<&dyn std::error::Error>` is not implemented for `&ArchiveError`
   |
   = note: the question mark operation (`?`) implicitly performs a conversion on the error value using the `From` trait
   = help: the following implementations were found:
             <ArchiveError as From<&'static (dyn std::error::Error + 'static)>>
   = note: required by `from`

    ArchiveZipError(#[from] &dyn std::error::Error),
    => Missing lifetime specifier [E0106]

删除

'静态

生存期说明符会导致此错误：

error[E0277]: `?` couldn't convert the error to `&ArchiveError`
  --> src/archive.rs:45:38
   |
42 | fn extract<R: Read + Seek>(filename: &'static str) -> Result<(), &ArchiveError> {
   |                                                       ------------------------- expected `&ArchiveError` because of this
...
45 |             ArchiveZip::new(filename)?
   |                                      ^ the trait `From<&dyn std::error::Error>` is not implemented for `&ArchiveError`
   |
   = note: the question mark operation (`?`) implicitly performs a conversion on the error value using the `From` trait
   = help: the following implementations were found:
             <ArchiveError as From<&'static (dyn std::error::Error + 'static)>>
   = note: required by `from`

    ArchiveZipError(#[from] &dyn std::error::Error),
    => Missing lifetime specifier [E0106]

使用此调用函数：

error[E0277]: `?` couldn't convert the error to `&ArchiveError`
  --> src/archive.rs:45:38
   |
42 | fn extract<R: Read + Seek>(filename: &'static str) -> Result<(), &ArchiveError> {
   |                                                       ------------------------- expected `&ArchiveError` because of this
...
45 |             ArchiveZip::new(filename)?
   |                                      ^ the trait `From<&dyn std::error::Error>` is not implemented for `&ArchiveError`
   |
   = note: the question mark operation (`?`) implicitly performs a conversion on the error value using the `From` trait
   = help: the following implementations were found:
             <ArchiveError as From<&'static (dyn std::error::Error + 'static)>>
   = note: required by `from`

    ArchiveZipError(#[from] &dyn std::error::Error),
    => Missing lifetime specifier [E0106]

fn提取（文件名：&'static str）->结果{
匹配从文件名（文件名）获取扩展名{
一些（“zip”）=>{
ArchiveZip:：新建（文件名）？
.摘录（“foo”）
.或（错误（&ArchiveError:：archiveziperor（&ziperor:：InvalidArchive（文件名）））
}
无=>错误（&ArchiveError:：ArchiveTypeNotDetectedError），
}
}

使用这些功能：

error[E0277]: `?` couldn't convert the error to `&ArchiveError`
  --> src/archive.rs:45:38
   |
42 | fn extract<R: Read + Seek>(filename: &'static str) -> Result<(), &ArchiveError> {
   |                                                       ------------------------- expected `&ArchiveError` because of this
...
45 |             ArchiveZip::new(filename)?
   |                                      ^ the trait `From<&dyn std::error::Error>` is not implemented for `&ArchiveError`
   |
   = note: the question mark operation (`?`) implicitly performs a conversion on the error value using the `From` trait
   = help: the following implementations were found:
             <ArchiveError as From<&'static (dyn std::error::Error + 'static)>>
   = note: required by `from`

    ArchiveZipError(#[from] &dyn std::error::Error),
    => Missing lifetime specifier [E0106]

impl for ArchiveZip结果{
让reader=ArchiveZip:：获取文件\读取器（路径）？；
Ok（&ArchiveZip{path，archive:ZipArchive:：new（reader）？}）
}
fn获取文件读取器（路径：&str）->结果{
确定（&mut文件：：打开（路径）？）
}
}

来自指令的

#如何不工作？
使用
框
而不是
&dyn Error
工作

我也改变了：

archiveziperor（#[from]&dyn std:：error:：error），

为此：

archiveziperor（#[来自]ziperor），
您的代码是。。。有问题的引用，
&T
，只借用它们引用的值，这意味着其他东西必须拥有它们。不幸的是，很多对象的所有者只是超出范围的函数中的变量/临时变量，这将导致生成的引用立即无效。错误通常拥有它们的数据，因此，如果您用
Box
@user4815162342替换
&'static dyn std:：error:：error
，您可能会得到更好的结果：如何让
Box
与
thisrerror:：error
自动转换东西的
指令一起工作？（并不是说我得到了它与参考无论如何，你可以看到从我的问题…）。我以前试过对结果类型和错误类型都使用
Box
，但它无法转换。@Neil您能提供一个小的、自给自足的示例来说明什么不适合您吗？我发现很难从你的问题中理解这一点。而
可提取的
特征来自哪里？如果这是您定义的，那么可能这就是问题的根源，因为它的
new
方法指定了极其奇怪的
Result
返回类型。