Scala Slick 3.1-将Slick表行对象转换为案例类
我已经使用Slick 3.1代码生成器创建了默认对象和trait Tables.scala 下面的方法可以工作,但是我想隐式或显式地将UserRow和PasswordsRow转换为User和UserPassword 工作方法:Scala Slick 3.1-将Slick表行对象转换为案例类,scala,slick,Scala,Slick,我已经使用Slick 3.1代码生成器创建了默认对象和trait Tables.scala 下面的方法可以工作,但是我想隐式或显式地将UserRow和PasswordsRow转换为User和UserPassword 工作方法: override def getUser(email: String): Future[Option[(Tables.UsersRow, Tables.PasswordsRow)]] = db.run { (for { user <- users if user
override def getUser(email: String): Future[Option[(Tables.UsersRow, Tables.PasswordsRow)]] = db.run {
(for {
user <- users if user.email === email
password <- passwords if password.id === user.id
} yield (user, password)).result.headOption
override def getUser(电子邮件:String):Future[Option[(Tables.UsersRow,Tables.PasswordsRow)]=db.run{
(用于{
用户可能是这样的吗
val futureUserRowAndPwdRow = getUser(email)
val futureUser: Future[Option[(User, UserPassword)]] = futureUserRowAndPwdRow map {
maybeUserRow => maybeUserRow map {
case (userRow, pwdRow) => (User(userRow.whatever....), UserPassword(..))
}
}
你能再解释一下吗?如果我理解正确的话,他有一个Future[Option[(Tables.UsersRow,Tables.PasswordsRow)]
,他想要一个Future[Option[(User,userpasswords)]]
。他只需要映射它,就可以得到他的案例类User
和UserPassword
,而不是行类……一点也不复杂。
package model
import com.wordnik.swagger.annotations.{ ApiModel, ApiModelProperty }
import slick.jdbc.GetResult
import spray.json.DefaultJsonProtocol
import scala.annotation.meta.field
case class User(
id: Int,
email: String,
name: Option[String] = None,
surname: Option[String] = None,
passwordId: Option[Int] = None
)
object User extends DefaultJsonProtocol{
implicit val getUserResult = GetResult(r => User(r.<<, r.<<, r.<<, r.<<, r.<<))
implicit val userFormat = jsonFormat5(User.apply)
}
package model
import com.github.t3hnar.bcrypt.{Password, generateSalt}
import slick.jdbc.GetResult
case class UserPassword(id: Int, hashedPassword: Option[String], salt: String = generateSalt) {
def passwordMatches(password: String): Boolean = hashedPassword.contains(password.bcrypt(salt))
}
object UserPassword {
implicit val getUserPasswordResult = GetResult(r => UserPassword(r.<<, r.<<, r.<<))
def newWithPassword(password: String) = {
val salt = generateSalt
new UserPassword(0, Some(password.bcrypt(salt)), salt)
}
}
val futureUserRowAndPwdRow = getUser(email)
val futureUser: Future[Option[(User, UserPassword)]] = futureUserRowAndPwdRow map {
maybeUserRow => maybeUserRow map {
case (userRow, pwdRow) => (User(userRow.whatever....), UserPassword(..))
}
}