Session 具有3个表和2个和组的内部联接

我有三张桌子；公司、培训票和考试

公司表：

培训票表：

测试会话表：

我需要这样的东西：

 C. CODE | COMPANY NAME | 1ST START DATE | TRAINING TICKET TOTAL | CERTIFIED TOTAL
 192      ABC ENTERPRISE  2015-02-02             2                1
 299      XYZ ENTERPRISE  2015-03-02             1                1 

有可能吗

我的Sql指令是：

Select *, count(TICKET.CCODE) AS TICKET_TOTAL, count(TEST.CODE) AS CERT_TOTAL
from TICKET 
Inner Join COMPANY on TICKET.CCODE = COMPANY.CCODE 
Inner Join TEST on COMPANY.CCODE = TEST.CCODE 
Group by (TICKET.CCODE),(TEST.CCODE)
Order by TICKET_TOTAL DESC

但对于TICKET_TOTAL和CERT_TOTAL，这两个计数总是等于相同的结果，并且总和是错误的——结果是TICKET_TOTAL=21，CERT_TOTAL=28，但我得到523——排名第一的公司。

我得到了答案：

Select COMPANY.CODE, COMPANY.NAME, 
MIN(TICKET.STARTDATE), count(TICKET.TICKETID) AS TICKET_TOTAL, 
count(TEST.CERTIFIED) AS CERT_TOTAL
    from COMPANY
    INNER JOIN TICKET ON COMPANY.CODE = TICKET.CCODE 
    LEFT JOIN TEST ON TICKET.TICKETID = TEST.TICKET
    Group by (TICKET.CCODE)
    ORDER BY TICKET_TOTAL DESC 

1-从公司表中重新排序和星型指示

2-MINTICKET.STARTDATE获取第一个开始日期，必要时使用MAX获取最后一个开始日期

3-将内部联接更改为左联接，因为有些公司在票证表上有票证，但在测试表上没有测试

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希望这能对以后的人有所帮助

普遍接受的做法是展示你迄今为止所做的努力，展示你在这个问题上付出了一些努力。@Coshman对我来说最大的问题是第二组和。我简化了表格，但一家公司的第一笔金额是28，第二笔金额是21。我能做的第一个和没有问题3个内部连接+1个组和-第二个组我得到了一些疯狂的结果，比如523。。这两个数字总是相等的。选择*，countTICKET.CCODE作为票证总数，countTEST.CODE作为来自票证上的票证内部加入公司的证书总数。CCODE=COMPANY.CCODE内部加入公司测试。CCODE=TEST.CCODE按票证分组。CCODE，TEST.CCODE按票证排序\u TOTAL DESC

 C. CODE | COMPANY NAME | 1ST START DATE | TRAINING TICKET TOTAL | CERTIFIED TOTAL
 192      ABC ENTERPRISE  2015-02-02             2                1
 299      XYZ ENTERPRISE  2015-03-02             1                1 

Select *, count(TICKET.CCODE) AS TICKET_TOTAL, count(TEST.CODE) AS CERT_TOTAL
from TICKET 
Inner Join COMPANY on TICKET.CCODE = COMPANY.CCODE 
Inner Join TEST on COMPANY.CCODE = TEST.CCODE 
Group by (TICKET.CCODE),(TEST.CCODE)
Order by TICKET_TOTAL DESC

Select COMPANY.CODE, COMPANY.NAME, 
MIN(TICKET.STARTDATE), count(TICKET.TICKETID) AS TICKET_TOTAL, 
count(TEST.CERTIFIED) AS CERT_TOTAL
    from COMPANY
    INNER JOIN TICKET ON COMPANY.CODE = TICKET.CCODE 
    LEFT JOIN TEST ON TICKET.TICKETID = TEST.TICKET
    Group by (TICKET.CCODE)
    ORDER BY TICKET_TOTAL DESC