Shell 将每行除以awk中的最大值

我试图将行除以该行中的最大值，就像所有列都是NA的行一样

    r1  r2  r3  r4
a   0   2.3 1.2 0.1
b   0.1 4.5 9.1 3.1
c   9.1 8.4 0   5

我明白了

    r1  r2  r3  r4
a   0   1   0.52173913  0.043478261
b   0.010989011 0.494505495 1   0.340659341
c   1   0.923076923 0   0.549450549

我试图通过执行

  awk '{m=$1;for(i=1;i<=NF;i++)if($i>m)m=$i;print m}' file.txt > max.txt

我正在尝试执行一个代码，其中最后一列将分割该行中的所有列，但首先我需要格式化每一行，因此我被卡住了

awk '{for(i=1;i<NF;i++) printf "%s " $i,$NF}' file1.txt

我试图打印该行的每个组合，然后在新行上打印下一行组合。但我想知道是否有更好的方法来做到这一点。

以下awk可能会对您有所帮助：

awk '
FNR==1{
  print;
  next
}
{
  len=""
  for(i=2;i<=NF;i++){
     len=len>$i?len:$i};
  printf("%s%s", $1, OFS)
}
{
  for(i=2;i<=NF;i++){
     printf("%s%s",$i>0?$i/len:0,i==NF?RS:FS)}
}
'    Input_file

说明：使用“立即解决方案”在此处添加说明：

awk '
FNR==1{  ##FNR==1 is a condition where it will check if it is first line of Input_file then do following:
  print; ##printing the current line then.
  next   ##next is awk out of the box keyword which will skip all further statements now.
}
{
  len="" ##variable named len(which contains the greatest value in a line here)
  for(i=2;i<=NF;i++){ ##Starting a for loop here starting from 2nd field to till value of NF which means it will cover all the fields on a line.
     len=len>$i?len:$i}; ##Creating a variable named len here whose value is $1 if it is NULL and if it is greater than current $1 then it remains same else will be $1
  printf("%s%s", $1, OFS) ##Printing the 1st column value here along with space.
}
{
  for(i=2;i<=NF;i++){ ##Starting a for loop here whose value starts from 2 to till the value of NF it covers all the field of current line.
     printf("%s%s",$i>0?$i/len:0,i==NF?RS:FS)} ##Printing current field divided by value of len varible(which has maximum value of current line), it also checks a conditoin if value of i equals to NF then print new line else print space.
}
'  Input_file          ##mentioning the Input_file name here.

以下awk可能会在相同方面帮助您：

awk '
FNR==1{
  print;
  next
}
{
  len=""
  for(i=2;i<=NF;i++){
     len=len>$i?len:$i};
  printf("%s%s", $1, OFS)
}
{
  for(i=2;i<=NF;i++){
     printf("%s%s",$i>0?$i/len:0,i==NF?RS:FS)}
}
'    Input_file

说明：使用“立即解决方案”在此处添加说明：

awk '
FNR==1{  ##FNR==1 is a condition where it will check if it is first line of Input_file then do following:
  print; ##printing the current line then.
  next   ##next is awk out of the box keyword which will skip all further statements now.
}
{
  len="" ##variable named len(which contains the greatest value in a line here)
  for(i=2;i<=NF;i++){ ##Starting a for loop here starting from 2nd field to till value of NF which means it will cover all the fields on a line.
     len=len>$i?len:$i}; ##Creating a variable named len here whose value is $1 if it is NULL and if it is greater than current $1 then it remains same else will be $1
  printf("%s%s", $1, OFS) ##Printing the 1st column value here along with space.
}
{
  for(i=2;i<=NF;i++){ ##Starting a for loop here whose value starts from 2 to till the value of NF it covers all the field of current line.
     printf("%s%s",$i>0?$i/len:0,i==NF?RS:FS)} ##Printing current field divided by value of len varible(which has maximum value of current line), it also checks a conditoin if value of i equals to NF then print new line else print space.
}
'  Input_file          ##mentioning the Input_file name here.

救命啊

$ awk 'NR>1 {m=$2; for(i=3;i<=NF;i++) if($3>m) m=$3; 
             for(i=2;i<=NF;i++) $i/=m}1' file

    r1  r2  r3  r4
a 0 1 0.521739 0.0434783
b 0.0222222 1 2.02222 0.688889
c 1 0.923077 0 0.549451

救命啊

$ awk 'NR>1 {m=$2; for(i=3;i<=NF;i++) if($3>m) m=$3; 
             for(i=2;i<=NF;i++) $i/=m}1' file

    r1  r2  r3  r4
a 0 1 0.521739 0.0434783
b 0.0222222 1 2.02222 0.688889
c 1 0.923077 0 0.549451

---

和你已经拿到了还是想拿到？到目前为止，你用awk写了什么？什么不起作用？请给出一个输入格式的最小示例。对于一个全为零的行，您希望打印什么？1或N或0或其他什么？谢谢你提出这个问题，我会把它添加到我的问题中..然后呢？你已经拿到了还是想拿到？到目前为止，你用awk写了什么？什么不起作用？请给出一个输入格式的最小示例。对于一个全为零的行，您希望打印什么？1或N或0或其他什么？谢谢你提出这个问题，我会把它添加到我的question@EdMorton，当然，先生，现在完成了，谢谢你一如既往的指导：@EdMorton，当然，先生，现在完成了，谢谢你一如既往的指导：