Sorting XSLT2.0中的xml排序问题有什么想法吗?
您好,我正在尝试按属性为“id”的元素“answer”的出现次数对xml进行排序,并获取简单摘要。Sorting XSLT2.0中的xml排序问题有什么想法吗?,sorting,count,xslt-2.0,Sorting,Count,Xslt 2.0,您好,我正在尝试按属性为“id”的元素“answer”的出现次数对xml进行排序,并获取简单摘要。 <person id="1"> <answer id="A"/> <answer id="B"/> </person> <person id="2"> <answer id="A"/> <answer id="C"/> </person> <person id="3"> <
<person id="1">
<answer id="A"/>
<answer id="B"/>
</person>
<person id="2">
<answer id="A"/>
<answer id="C"/>
</person>
<person id="3">
<answer id="C"/>
</person>
我只需要输出摘要文本:
<xsl:for-each select="distinct-values(/person/answer)">
<xsl:sort select="count(/person/answer)" data-type="number"/>
<xsl:value-of select="./@id"/> =
<xsl:value-of select="count(/person/answer[@id=./@id])"/> time(s)
</xsl:for-each>
A=2次C=2次
B=1次(s) 我在XSLT2.0中尝试过:
<xsl:for-each select="distinct-values(/person/answer)">
<xsl:sort select="count(/person/answer)" data-type="number"/>
<xsl:value-of select="./@id"/> =
<xsl:value-of select="count(/person/answer[@id=./@id])"/> time(s)
</xsl:for-each>
=
时间(s)
但它不起作用:在XMLSpy 2008中:
“XPath 2.0表达式中的错误不是节点项” 在撒克逊9中:
XPTY0020:前导“/”无法选择包含上下文项的树的根节点:上下文项是原子值
未能编译样式表。检测到1个错误。我将对每组中的项目进行分组和计数:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:for-each-group select="//person/answer" group-by="@id">
<xsl:sort select="count(current-group())" order="descending"/>
<xsl:value-of select="concat(current-grouping-key(), ' = ', count(current-group()), ' time(s). ')"/>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
A = 2 time(s).
C = 2 time(s).
B = 1 time(s).