Spring 弹簧404错误
我正在尝试运行spring应用程序,但是我得到了404错误。有人能帮忙吗? 我从mkyong站点获取此代码。他举的例子是有效的,但我试图从头开始做所有事情,但它不起作用Spring 弹簧404错误,spring,spring-mvc,Spring,Spring Mvc,我正在尝试运行spring应用程序,但是我得到了404错误。有人能帮忙吗? 我从mkyong站点获取此代码。他举的例子是有效的,但我试图从头开始做所有事情,但它不起作用 package com.mkyong.common.controller; import org.springframework.stereotype.Controller; import org.springframework.ui.ModelMap; import org.springframework.web.bi
package com.mkyong.common.controller;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
@RequestMapping("/welcome")
public class HelloController {
@RequestMapping(method = RequestMethod.GET)
public String printWelcome(ModelMap model) {
model.addAttribute("message", "Spring 3 MVC Hello World");
return "hello";
}
}
hello.jsp
<html>
<body>
<h1>Message : ${message}</h1>
</body>
</html>
mvc-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.mkyong.common.controller" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
web.xml
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring Web MVC Application</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
将*添加到web.xml中servlet的URL模式中:
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
在方法上使用@RequestMapping/welcome,而不是类它不起作用。我创建了一个maven项目以及从工作示例中复制和粘贴的所有代码。但这也没有帮助。您在浏览器中键入了什么URI,servlet的上下文路径是什么?,/WEB-INF/mvc-dispatcher-servlet.xml。我有index.jsp,它将转发到欢迎页面,所以我猜/SpringMVC是上下文路径。您的控制器具有/welcome的请求映射。试试看。我想我在maven项目结构中犯了错误。我创建了动态web项目,并将这些代码放在上面,它工作正常。从启动到404请求,是否可以添加日志消息?