Sql server 2005 SQL Server别名中两个varchar列的总和

我有一张如下所示的表格

declare @Location Table([state] nvarchar(30) null,city nvarchar(30) null)

Insert Into @Location Values('California', 'San Francisco')
Insert Into @Location Values('California', null)
Insert Into @Location Values('California', 'Orange County')
Insert Into @Location Values('California', null)

select 
    [state], city, [state] as CurrentState, 
    case 
       when city is null then 'Sacramento' 
       else city 
    end as CurrentCity  
from 
    @Location

和select语句，如下所示

declare @Location Table([state] nvarchar(30) null,city nvarchar(30) null)

Insert Into @Location Values('California', 'San Francisco')
Insert Into @Location Values('California', null)
Insert Into @Location Values('California', 'Orange County')
Insert Into @Location Values('California', null)

select 
    [state], city, [state] as CurrentState, 
    case 
       when city is null then 'Sacramento' 
       else city 
    end as CurrentCity  
from 
    @Location

我想要第五列，标题为

Address

，它给出了

CurrentState

和

CurrentCity

列的总和，如下所示：

Address
California, San Francisco
California, Sacramento
California, Orange County
California, Sacramento

这可能吗

---

我已经试过了

CurrentState+，'+CurrentCity

。它不起作用

这将满足您的要求：

select [state], city, [state] as CurrentState, 
       coalesce(city, 'Sacramento') as CurrentCity, 
       (coalesce(city, 'Sacramento') + ', ' + coalesce(state, '')) as Address, 
from @Location;

也就是说，你需要重复这个逻辑。但是

coalesce（）

比

case

语句要简单得多。

这同样有效

select 
    [state], city, [state] as CurrentState, 
    case 
       when city is null then 'Sacramento' 
       else city 
    end as CurrentCity,
    case 
       when city is null then [state] + ', ' + 'Sacramento' 
       else [state] + ', ' + [city]
    end as Address

from 
    @Location

要不是更干净的方法，我宁愿

SELECT
    [STATE]
    ,[CITY]
    ,CurrentState = [STATE]
    ,CurrentCity = ISNULL ([CITY] , 'Sacramento')
    ,Address = [STATE] + ', ' + ISNULL ([CITY] , 'Sacramento')
FROM @Location

或

我知道您已经标记了SQLServer2005，但是，如果您在未来的SQLServer2012中使用，您甚至可以尝试使用IIF语句作为

SELECT
    [STATE]
    ,[CITY]
    ,CurrentState = [STATE]
    ,CurrentCity = IIF([CITY] IS NULL,'Sacramento',[CITY])
    ,Address= IIF([CITY] IS NULL,
                  [STATE] + ', ' +'Sacramento',
                   [STATE] + ', ' +[CITY])
FROM @Location

或使用选择，如下所示

SELECT
    [STATE]
    ,[CITY]
    ,CurrentState = [STATE]
    ,CurrentCity = CHOOSE(IIF([CITY] IS NULL,1,2),'Sacramento',[CITY])
    ,Address= CHOOSE(IIF([CITY] IS NULL,1,2),[STATE] + ', ' +'Sacramento',[STATE] + ', ' +[CITY])   
FROM @Location

所有这些都会产生相同的结果

---

希望这会有帮助。

只需执行

city+，“+state

@Gordon:city，state会给我实际的列值和空值。这一定是化名，谢谢戈登。这很有帮助。