Sql server 如何查询表中来自2个日期范围的数据

我想比较两个不同日期范围的数据。我希望数据显示在同一个数据集中，具有daterange1和daterange2的不同列。以下是我现在拥有的：

SELECT l1.Name, t1.SectionID, 
SUM(SectionItems) AS ItemCount, 
SUM(SectionSales) AS Sales, 
SUM(SectionCost) AS Cost, 
(((SUM(SectionSales) - SUM(SectionCost))/ SUM(SectionSales)) * 100) AS Margin
FROM StoreSectionSales t1
JOIN Sections l1 ON l1.SectionID = t1.SectionID AND l1.StoreID = t1.StoreID
WHERE TimeID <= (SELECT TimeID FROM Time WHERE FactDate = '11/15/2015') 
    AND TimeID <= (SELECT TimeID FROM Time WHERE FactDate = '11/15/2016') 
    AND t1.StoreID <> 08
GROUP BY t1.SectionID, l1.Name
ORDER BY t1.SectionID

我想从两个不同的日期范围运行查询，然后将Item Count sales cost和margin的列添加到结果集中，并将它们添加到相应的部分。我尝试了一个子查询，但是这会将所有数据添加到一起，然后将该数据应用到所有行

谢谢。

试试这个：

select time1.name, time1.sectionID, 
time1.ItemCount as ItemCount1, time1.Sales as Sales1, 
time2.ItemCount as ItemCount2, time2.Sales as Sales2
from
(SELECT l1.Name, t1.SectionID, 
    SUM(SectionItems) AS ItemCount, 
    SUM(SectionSales) AS Sales, 
    SUM(SectionCost) AS Cost, 
    (((SUM(SectionSales) - SUM(SectionCost))/ SUM(SectionSales)) * 100) AS Margin
    FROM StoreSectionSales t1
    inner join Sections l1 ON l1.SectionID = t1.SectionID AND l1.StoreID = t1.StoreID
    WHERE TimeID <= (SELECT TimeID FROM Time WHERE FactDate = '11/15/2015') 
    AND t1.StoreID <> 08
GROUP BY t1.SectionID, l1.Name) time1
inner join 
(SELECT l1.Name, t1.SectionID, 
    SUM(SectionItems) AS ItemCount, 
    SUM(SectionSales) AS Sales, 
    SUM(SectionCost) AS Cost, 
    (((SUM(SectionSales) - SUM(SectionCost))/ SUM(SectionSales)) * 100) AS Margin
    FROM StoreSectionSales t1
    inner join Sections l1 ON l1.SectionID = t1.SectionID AND l1.StoreID = t1.StoreID
    WHERE TimeID <= (SELECT TimeID FROM Time WHERE FactDate = '11/15/2016') 
        AND t1.StoreID <> 08
    GROUP BY t1.SectionID, l1.Name) time2 on time1.name = time2.name
order by time1.sectionID;

我遗漏了一些专栏，但你明白了。

试试这个：

select time1.name, time1.sectionID, 
time1.ItemCount as ItemCount1, time1.Sales as Sales1, 
time2.ItemCount as ItemCount2, time2.Sales as Sales2
from
(SELECT l1.Name, t1.SectionID, 
    SUM(SectionItems) AS ItemCount, 
    SUM(SectionSales) AS Sales, 
    SUM(SectionCost) AS Cost, 
    (((SUM(SectionSales) - SUM(SectionCost))/ SUM(SectionSales)) * 100) AS Margin
    FROM StoreSectionSales t1
    inner join Sections l1 ON l1.SectionID = t1.SectionID AND l1.StoreID = t1.StoreID
    WHERE TimeID <= (SELECT TimeID FROM Time WHERE FactDate = '11/15/2015') 
    AND t1.StoreID <> 08
GROUP BY t1.SectionID, l1.Name) time1
inner join 
(SELECT l1.Name, t1.SectionID, 
    SUM(SectionItems) AS ItemCount, 
    SUM(SectionSales) AS Sales, 
    SUM(SectionCost) AS Cost, 
    (((SUM(SectionSales) - SUM(SectionCost))/ SUM(SectionSales)) * 100) AS Margin
    FROM StoreSectionSales t1
    inner join Sections l1 ON l1.SectionID = t1.SectionID AND l1.StoreID = t1.StoreID
    WHERE TimeID <= (SELECT TimeID FROM Time WHERE FactDate = '11/15/2016') 
        AND t1.StoreID <> 08
    GROUP BY t1.SectionID, l1.Name) time2 on time1.name = time2.name
order by time1.sectionID;

---

我漏掉了一些列，但你明白了。

请发布你想要的结果。结果将包含以下列：名称、SectionID、ItemCount1、Sales1、Cost1、Margin1、ItemCount2、Sales2、Cost2、Margin2。带1的列将来自第一个日期范围，带2的列将来自第二个日期范围。请发布您想要的结果。结果将包含以下列：名称、SectionID、ItemCount1、Sales1、Cost1、Margin1、ItemCount2、Sales2、Cost2、Margin2。带1的列将来自第一个日期范围，带2的列将来自第二个日期范围