Sql server 如何获取字符串sql中某些字符之后的所有字符
我有一个列,其中包含具有以下形式字符串的行:Sql server 如何获取字符串sql中某些字符之后的所有字符,sql-server,string,tsql,Sql Server,String,Tsql,我有一个列,其中包含具有以下形式字符串的行: #S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13 我希望能够获得所有行的以下结果: 01,09,10,13 我正在使用tsql,并尝试了以下操作: SUBSTRING(E.REJECT_WF_NOS, CHARINDEX('.', E.REJECT_WF_NOS) + 1, LEN(E.REJECT_WF_NOS)) 我可能会把它们分开,因为结构不是恒定的。您似乎只需要小数点后的值。这将分割逗号上的值,然后获取小
#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13
我希望能够获得所有行的以下结果:
01,09,10,13
我正在使用tsql,并尝试了以下操作:
SUBSTRING(E.REJECT_WF_NOS, CHARINDEX('.', E.REJECT_WF_NOS) + 1, LEN(E.REJECT_WF_NOS))
我可能会把它们分开,因为结构不是恒定的。您似乎只需要小数点后的值。这将分割逗号上的值,然后获取小数点后的所有内容,然后将其重新压缩为字符串
declare @var varchar(64) = 'S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13'
SELECT
STUFF((
SELECT ',' + substring(item,charindex('.',Item) + 1,32)
FROM dbo.DelimitedSplit8K(@var,',')
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
/* "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
enough to cover VARCHAR(8000)*/
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
;
GO
declare @var varchar(64) = 'S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13'
SELECT
STUFF((
SELECT ',' + substring(item,charindex('.',Item) + 1,32)
FROM dbo.DelimitedSplit8K(@var,',')
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
/* "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
enough to cover VARCHAR(8000)*/
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
;
GO
这里有一个简单的2016版本,如果您希望它基于行
select reverse(substring(reverse(value),1,2)),* from
string_split('#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13',',')
结果多行-2016:
**
如果你只想让它排成一行,这可能是2016年的方式
DECLARE @MyTable TABLE
(
ID int ,
Strings varchar(10)
)
INSERT INTO @MyTable (ID,Strings)
select 1,reverse(substring(reverse(value),1,2)) as SplittedValues
from string_split('#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13',',')
---Select * from @MyTable
SELECT ID, NewVales = STUFF((SELECT N', ' + Strings
FROM @MyTable AS p2
WHERE p2.ID = p.ID
ORDER BY Strings
FOR XML PATH(N'')), 1, 2, N'')
FROM @MyTable AS p
GROUP BY ID
ORDER BY ID;
2016年第1排结果
为此,您甚至不需要拆分器;您可以使用parsename来“拆分”这些值
declare @string varchar(100) = '#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13';
select newString = stuff
(( select ','+substring(item, 1, charindex(',', item)-1)
from (values (4),(3),(2),(1)) t(n)
cross apply (values (substring(@string, charindex('.',@string)+1, 8000)+',')) s(string)
cross apply (values (parsename(string,n))) split(item)
for xml path('')), 1,1,'');
这将比DSPLIT8K更快,并且不需要SQL Server 2016。在SQL Server 2017上,您可以进一步简化,如下所示:
select string_agg(substring(item, 1, charindex(',', item)-1),',')
from (values (4),(3),(2),(1)) t(n)
cross apply (values (substring(@string, charindex('.',@string)+1, 8000)+',')) s(string)
cross apply (values (parsename(string,n))) split(item)
如果您的数据类似于下表结构中的逐行数据:
ID DATA
1 #S6TF3.01
2 #S6TF3.09
3 #S6TF3.10
4 #S6TF3.13
如果您总是有如上所述的数据,那么只需按如下所示编写子字符串函数:
SELECT SUBSTRING(DATA, 8, 2) DATA from #TEMP
结果:
ID DATA Result
1 #S6TF3.01 01
2 #S6TF3.09 09
3 #S6TF3.10 10
4 #S6TF3.13 13
如果数据库的结构是这样的,那么它就不太好了……如果十进制后面总是有2个数字,我会在2016年使用字符串_split,用逗号拆分,然后颠倒行和子字符串2,然后再颠倒:)做得好。不过,我会将nvarchar(max)改为varchar(64)。该值>数据类型定义输出字符串的数据类型,这意味着您将在varchar(64)执行时返回一个nvarchar(max)。而且转换是隐式的。请注意,该函数不需要SQL Server 2016,但如果值不超过4个,我喜欢parsename。