Sql server SQL SERVER：连接XML列的节点值

下表中有一列是XML格式的：

身份证件 标签 细节 1 测试1

email11@foo.comemail12@foo.comblabla

2 测试2

email21@foo.comemail22@foo.comblabla

---

请尝试以下解决方案

因为没有提供DDL和样本数据填充， 假设Details列是XML数据类型

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, Label VARCHAR(20), Details XML);
INSERT INTO @tbl (Label, Details) VALUES
('Test1',N'<terms><destination><email>email11@foo.com</email><email>email12@foo.com</email></destination><content>blabla</content></terms>'),
('Test2',N'<terms><destination><email>email21@foo.com</email><email>email22@foo.com</email></destination><content>blabla</content></terms>');
-- DDL and sample data population, end

SELECT ID, Label 
    , REPLACE(Details.query('data(/terms/destination/email/text())').value('.','VARCHAR(MAX)'), SPACE(1), ', ') AS Destination
FROM @tbl;

+----+-------+----------------------------------+
| ID | Label |           Destination            |
+----+-------+----------------------------------+
|  1 | Test1 | email11@foo.com, email12@foo.com |
|  2 | Test2 | email21@foo.com, email22@foo.com |
+----+-------+----------------------------------+

select ID, Label,
    stuff(
        details.query('for $step in /terms/destination/email/text() return concat(", ", string($step))')
        .value('.', 'nvarchar(max)'),
    1, 2, '')
from @tbl;