Sql server 获取SQL SERVER中运行的日期总数

我想创建一个连续的日期列表，在上面的日期基础上增加6周。到目前为止，我的代码给了我一个开始和结束日期。我需要显示开始日期和结束日期之间的6周间隔

aLearnerRef     startdate     enddate       reviewdate
------------------------------------------------------
399750423600    2013-11-27    2014-06-12    2014-01-08
399750423600    2013-11-27    2014-06-12    2014-02-19
399750423600    2013-11-27    2014-06-12    2014-04-02
399750423600    2013-11-27    2014-06-12    2014-05-14

我希望它循环，直到它到达enddate之前的最后一个日期。我想不出一个可能的办法来做这件事。以下是到目前为止我拥有的代码：

SELECT a.aLearnerRef,  x.startdate, x.enddate
FROM aims a
inner join vStudyP s
on s.LearnerRef = a.aLearnerRef
join (SELECT aLearnerRef, min(learnstartdate) startdate, max(learnplannedenddate) enddate
        FROM aims
        GROUP BY aLearnerRef) x
on a.aLearnerRef = x.aLearnerRef
group by a.aLearnerRef,  x.startdate, x.enddate

试试这个代码

with cte as
(
select ak.akid,sdate,edate,DATEADD(WEEK,6,sdate) rdate from ak
Union All

select ak.akid,ak.sdate,ak.edate,DATEADD(WEEK,6,rdate) rdate from ak
inner join cte on  rdate between ak.sdate and ak.edate 
where  DATEADD(WEEK,6,rdate) between ak.sdate and ak.edate 


)
select * from CTE

如果有多个记录

with cte as
    (
    select ak.akid,sdate,edate,DATEADD(WEEK,6,sdate) rdate from ak
    Union All

    select ak.akid,ak.sdate,ak.edate,DATEADD(WEEK,6,rdate) rdate from ak
    inner join cte on  rdate between ak.sdate and ak.edate 
    where  DATEADD(WEEK,6,rdate) between ak.sdate and ak.edate 
          and cte.akid = ak.akid

    )
    select * from CTE

---

演示链接，使用辅助编号表：

SELECT a.aLearnerRef,  dateadd(day,n,a.startdate), a.enddate
FROM aims a
inner join numbers num
on n < datediff(day,startdate, enddate)

选择a.aLearnerRef、dateadd（day、n、a.startdate）、a.enddate
从目标a
内连接数
在n

我认为递归CTE在这里很有用。将尝试一些代码和共享。谢谢，这很有意义。如果ak中有超过1条记录呢？那么您希望对每一条记录都遵循相同的模式吗？如果您只想将此ans用于一条记录，则可以在两条select语句中应用where子句。所以这取决于你的要求。我认为它也适用于多张唱片。仍将编辑第二个选项（&post）仅添加一个条件。如果您对ans.感到满意，请将ans.标记为有用。