Sql server 每周都有结果

我需要您按日期订购一个查询，然后如果可以简化它：-）

此查询将返回从当前日期开始每周的条目数

以下是查询：

SELECT CONVERT(VarChar(50), DATEADD(day, DATEDIFF(day, 0, GETDATE()), -7), 103) as periode_join, COUNT(u.usr_ID) as cptu 
FROM [USR_USER] u 
INNER JOIN [USI_USER_SITE] s ON u.USR_ID = s.USR_ID
WHERE u.[USR_JOINED_DT] >=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -7) and u.[USR_JOINED_DT] <=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), 0)

UNION

SELECT CONVERT(VarChar(50), DATEADD(day, DATEDIFF(day, 0, GETDATE()), -14), 103) as periode_join, COUNT(u.usr_ID) as cptu 
FROM [USR_USER] u 
INNER JOIN [USI_USER_SITE] s ON u.USR_ID = s.USR_ID
WHERE u.[USR_JOINED_DT] >=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -14) and u.[USR_JOINED_DT] <=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -7)   

UNION

SELECT CONVERT(VarChar(50), DATEADD(day, DATEDIFF(day, 0, GETDATE()), -21), 103) as periode_join, COUNT(u.usr_ID) as cptu 
FROM [USR_USER] u 
INNER JOIN [USI_USER_SITE] s ON u.USR_ID = s.USR_ID
WHERE u.[USR_JOINED_DT] >=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -21) and u.[USR_JOINED_DT] <=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -14)

UNION

SELECT CONVERT(VarChar(50), DATEADD(day, DATEDIFF(day, 0, GETDATE()), -28), 103) as periode_join, COUNT(u.usr_ID) as cptu 
FROM [USR_USER] u 
INNER JOIN [USI_USER_SITE] s ON u.USR_ID = s.USR_ID
WHERE u.[USR_JOINED_DT] >=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -28) and u.[USR_JOINED_DT] <=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -21)   

 UNION

SELECT CONVERT(VarChar(50), DATEADD(day, DATEDIFF(day, 0, GETDATE()), -35), 103) as periode_join, COUNT(u.usr_ID) as cptu  
FROM [USR_USER] u 
INNER JOIN [USI_USER_SITE] s ON u.USR_ID = s.USR_ID
WHERE u.[USR_JOINED_DT] >=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -35) and u.[USR_JOINED_DT] <=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -28)   

UNION

SELECT CONVERT(VarChar(50), DATEADD(day, DATEDIFF(day, 0, GETDATE()), -42), 103) as periode_join, COUNT(u.usr_ID) as cptu 
FROM [USR_USER] u 
INNER JOIN [USI_USER_SITE] s ON u.USR_ID = s.USR_ID
WHERE u.[USR_JOINED_DT] >=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -42) and u.[USR_JOINED_DT] <=  DATEADD(day, DATEDIFF(day, 0, GETDATE()), -35)
ORDER BY periode_join desc

---

非常感谢：-D

如果您有SQL Server 2005及以上版本，您可以尝试以下内容：

;with CTE_Data as
(
  select
        u.usr_id,
        cast(dateadd(dd, -(datediff(dd, u.usr_joined_dt, getdate()) / 7 + 1) * 7, getdate()) as date) as periode_join
    from usr_user as u 
        inner join usi_user_site as s on u.usr_id = s.usr_id
)
select periode_join, count(usr_id) as cptu
from CTE_Data
group by periode_join
order by periode_join asc

要按周分割数据，我们必须计算getdate（）和表中date-Diff（dd，u.usr\u joined\u dt，getdate（））中日期之间的天数差，然后我们必须得到整周数-

/7

，然后我们必须减去整周数+1

---

例如，如果date=

'2013/06/30'

那么天数=9，整周数=1，我们必须减去1+1周，这样我们就得到了

'2013/06/25

，等等，你在使用哪个版本的SQL Server？是的，它可以工作，但你能解释一下这一行吗：

cast（dateadd（dd），（datediff）（dd，u.usr_加入_dt，getdate（））/7+1）*7，getdate（））作为日期）作为周期加入

;with CTE_Data as
(
  select
        u.usr_id,
        cast(dateadd(dd, -(datediff(dd, u.usr_joined_dt, getdate()) / 7 + 1) * 7, getdate()) as date) as periode_join
    from usr_user as u 
        inner join usi_user_site as s on u.usr_id = s.usr_id
)
select periode_join, count(usr_id) as cptu
from CTE_Data
group by periode_join
order by periode_join asc