Sql server 两个表的3个值之间的差异

我有两张像这样的桌子

id  att1 att2
1   34    56
2   45    12
3   34    11


id  att1 att2
1   14    10
2   25    2
3   14    10

如何获得3个值之间的差值，如

id      att1      att2
1-1=0  34-14=20  56-10=46
2-2=0  45-25=20  12-2 =10  
3-3=0  34-14=20  11-10=1 


SELECT A.id-B.id, A.att1-B.att1,A.att2-B.att2 from TABLEA as A join TABLEB as B...

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你真的不想从一个id中减去另一个id，是吗

SELECT
  A.id,
  A.att1 - B.att1,
  A.att2 - B.att2
FROM
  A JOIN B ON A.id = B.id

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你真的不想从一个id中减去另一个id，是吗

SELECT
  A.id,
  A.att1 - B.att1,
  A.att2 - B.att2
FROM
  A JOIN B ON A.id = B.id

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不确定您要找的是您在问题中尚未提供的内容。你是说这样的事吗

SELECT
    CAST(A.id AS VARCHAR(200)) + '-' +  CAST(B.id AS VARCHAR(200)) + '=' + CAST(A.id - B.id AS VARCHAR(200)) id
    ,CAST(A.att1 AS VARCHAR(200)) + '-' +  CAST(B.att1 AS VARCHAR(200)) + '=' + CAST(A.att1 - B.att1 AS VARCHAR(200)) att1
    ,CAST(A.att2 AS VARCHAR(200)) + '-' +  CAST(B.att2 AS VARCHAR(200)) + '=' + CAST(A.att2 - B.att2 AS VARCHAR(200)) att2
FROM
    TABLEA A
    INNER JOIN TABLEB B ON A.id = B.id

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不确定您要找的是您在问题中尚未提供的内容。你是说这样的事吗

SELECT
    CAST(A.id AS VARCHAR(200)) + '-' +  CAST(B.id AS VARCHAR(200)) + '=' + CAST(A.id - B.id AS VARCHAR(200)) id
    ,CAST(A.att1 AS VARCHAR(200)) + '-' +  CAST(B.att1 AS VARCHAR(200)) + '=' + CAST(A.att1 - B.att1 AS VARCHAR(200)) att1
    ,CAST(A.att2 AS VARCHAR(200)) + '-' +  CAST(B.att2 AS VARCHAR(200)) + '=' + CAST(A.att2 - B.att2 AS VARCHAR(200)) att2
FROM
    TABLEA A
    INNER JOIN TABLEB B ON A.id = B.id

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这两个表应该至少有一个匹配列，否则，如何？我将使用的ID，但如何完成查询然后检查@John Pick answer。这两个表应该至少有一个匹配的列，否则，如何？我将使用的ID，但如何完成查询然后检查@John Pick answer。你想要达到的目标应该是好的。