Sql 从非工作日计数中删除重叠小时数
需要您的帮助才能完成此任务 二月总共有696小时Sql 从非工作日计数中删除重叠小时数,sql,oracle,Sql,Oracle,需要您的帮助才能完成此任务 二月总共有696小时 Start Date End Date S1 - 01-Feb-16 04:00 - 02-Feb-16 10:00 - 30hrs S2 - 02-Feb-16 14:00 - 06-Feb-16 20:00 - 102hrs S3 - 01-Feb-16 01:00 - 02-Feb-16 07:00 - 30hrs Total Worked hrs - 162 hrs 由于S
Start Date End Date
S1 - 01-Feb-16 04:00 - 02-Feb-16 10:00 - 30hrs
S2 - 02-Feb-16 14:00 - 06-Feb-16 20:00 - 102hrs
S3 - 01-Feb-16 01:00 - 02-Feb-16 07:00 - 30hrs
Total Worked hrs - 162 hrs
由于S1和S3的可用时间重叠为27小时,因此总工作时间为135小时
预期查询结果为561小时
我对代码有一个挑战
1.代码准备好了,除了忽略重叠时间之外,其他部分需要您的帮助。
2.如何将查询限制为仅对sysdate月进行验证
Query:
SELECT ( ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 ) - TRUNC( SYSDATE, 'MM' )
- SUM( End_Date - Start_Date ) ) * 24 AS Unworked_Hours
FROM Trip_Dates;
Oracle安装程序:
CREATE TABLE Trip_Dates ( Start_Date, End_Date ) AS
SELECT TO_DATE( '2016-02-01 04:00:00', 'YYYY-MM-DD HH24:MI:SS' ), TO_DATE( '2016-02-02 10:00:00', 'YYYY-MM-DD HH24:MI:SS' ) FROM DUAL UNION ALL
SELECT TO_DATE( '2016-02-02 14:00:00', 'YYYY-MM-DD HH24:MI:SS' ), TO_DATE( '2016-02-06 20:00:00', 'YYYY-MM-DD HH24:MI:SS' ) FROM DUAL UNION ALL
SELECT TO_DATE( '2016-02-01 01:00:00', 'YYYY-MM-DD HH24:MI:SS' ), TO_DATE( '2016-02-02 07:00:00', 'YYYY-MM-DD HH24:MI:SS' ) FROM DUAL;
WITH Dates ( dt, start_end ) AS (
SELECT GREATEST( start_date, TRUNC( SYSDATE, 'MM' ) ),
1
FROM trip_dates
WHERE start_date < ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 )
AND end_date > TRUNC( SYSDATE, 'MM' )
UNION ALL
SELECT LEAST( end_date, ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 ) ),
-1
FROM trip_dates
WHERE start_date < ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 )
AND end_date > TRUNC( SYSDATE, 'MM' )
ORDER BY 1, 2
)
,range_start_ends ( dt, start_end, range_start, range_end ) AS (
SELECT d.*,
CASE
WHEN start_end = 1
AND SUM( start_end ) OVER ( ORDER BY dt ) = 1
THEN dt
ELSE NULL
END,
CASE
WHEN start_end = -1
AND SUM( start_end ) OVER ( ORDER BY dt ) = 0
THEN dt
ELSE NULL
END
FROM Dates d
),
worked_days ( worked_days ) AS (
SELECT range_end - LAG( range_start ) IGNORE NULLS OVER ( ORDER BY dt )
FROM range_start_ends
)
SELECT ( ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 )
- TRUNC( SYSDATE, 'MM' ) -
SUM( worked_days )
) * 24 AS unworked_hours
FROM worked_days;
UNWORKED_HOURS
--------------
561
查询:
CREATE TABLE Trip_Dates ( Start_Date, End_Date ) AS
SELECT TO_DATE( '2016-02-01 04:00:00', 'YYYY-MM-DD HH24:MI:SS' ), TO_DATE( '2016-02-02 10:00:00', 'YYYY-MM-DD HH24:MI:SS' ) FROM DUAL UNION ALL
SELECT TO_DATE( '2016-02-02 14:00:00', 'YYYY-MM-DD HH24:MI:SS' ), TO_DATE( '2016-02-06 20:00:00', 'YYYY-MM-DD HH24:MI:SS' ) FROM DUAL UNION ALL
SELECT TO_DATE( '2016-02-01 01:00:00', 'YYYY-MM-DD HH24:MI:SS' ), TO_DATE( '2016-02-02 07:00:00', 'YYYY-MM-DD HH24:MI:SS' ) FROM DUAL;
WITH Dates ( dt, start_end ) AS (
SELECT GREATEST( start_date, TRUNC( SYSDATE, 'MM' ) ),
1
FROM trip_dates
WHERE start_date < ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 )
AND end_date > TRUNC( SYSDATE, 'MM' )
UNION ALL
SELECT LEAST( end_date, ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 ) ),
-1
FROM trip_dates
WHERE start_date < ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 )
AND end_date > TRUNC( SYSDATE, 'MM' )
ORDER BY 1, 2
)
,range_start_ends ( dt, start_end, range_start, range_end ) AS (
SELECT d.*,
CASE
WHEN start_end = 1
AND SUM( start_end ) OVER ( ORDER BY dt ) = 1
THEN dt
ELSE NULL
END,
CASE
WHEN start_end = -1
AND SUM( start_end ) OVER ( ORDER BY dt ) = 0
THEN dt
ELSE NULL
END
FROM Dates d
),
worked_days ( worked_days ) AS (
SELECT range_end - LAG( range_start ) IGNORE NULLS OVER ( ORDER BY dt )
FROM range_start_ends
)
SELECT ( ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 )
- TRUNC( SYSDATE, 'MM' ) -
SUM( worked_days )
) * 24 AS unworked_hours
FROM worked_days;
UNWORKED_HOURS
--------------
561